Difference between revisions of "2017 AMC 8 Problems/Problem 4"
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==Solution== | ==Solution== | ||
We can approximate <math>7,928,564</math> to <math>8,000,000,</math> and <math>0.000315</math> to <math>0.0003.</math> Multiplying the two yields <math>2400.</math> This gives our answer to be <math>\boxed{\textbf{(D)}\ 2400}.</math> | We can approximate <math>7,928,564</math> to <math>8,000,000,</math> and <math>0.000315</math> to <math>0.0003.</math> Multiplying the two yields <math>2400.</math> This gives our answer to be <math>\boxed{\textbf{(D)}\ 2400}.</math> | ||
| + | |||
| + | ==See Also== | ||
| + | {{AMC8 box|year=2017|num-b=3|num-a=5}} | ||
| + | |||
| + | {{MAA Notice}} | ||
Revision as of 15:24, 22 November 2017
Problem 4
When 
is multiplied by 
the product is closest to which of the following?
Solution
We can approximate to 
and to 
Multiplying the two yields 
This gives our answer to be 
See Also
| 2017 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
