https://artofproblemsolving.com/wiki/index.php?title=2018_AMC_10A_Problems/Problem_14&feed=atom&action=history
2018 AMC 10A Problems/Problem 14 - Revision history
2024-03-29T02:16:26Z
Revision history for this page on the wiki
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https://artofproblemsolving.com/wiki/index.php?title=2018_AMC_10A_Problems/Problem_14&diff=200354&oldid=prev
Ashwin.s: /* Solution 6 (eyeball it) */
2023-10-27T15:59:25Z
<p><span dir="auto"><span class="autocomment">Solution 6 (eyeball it)</span></span></p>
<table class="diff diff-contentalign-left" data-mw="interface">
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<col class="diff-marker" />
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<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">← Older revision</td>
<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">Revision as of 15:59, 27 October 2023</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l56" >Line 56:</td>
<td colspan="2" class="diff-lineno">Line 56:</td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>A faster solution. Recognize that for exponents of this size <math>3^{n}</math> will be enormously greater than <math>2^{n}</math>, so the terms involving <math>2</math> will actually have very little effect on the quotient. Now we know the answer will be very close to <math>81</math>.</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>A faster solution. Recognize that for exponents of this size <math>3^{n}</math> will be enormously greater than <math>2^{n}</math>, so the terms involving <math>2</math> will actually have very little effect on the quotient. Now we know the answer will be very close to <math>81</math>.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'>−</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>Notice that the terms being added on to the top and bottom are in the ratio <math>\frac{1}{16}</math> with each other, so they must pull the ratio down from 81 very slightly. (In the same way that a new test score lower than your current cumulative grade always must pull that grade downward.) Answer: <math>\boxed{\text{(A)}}</math>.</div></td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>Notice that the terms being added on to the top and bottom are in the ratio <math>\frac{1}{16}</math> with each other, so they must pull the ratio down from 81 very slightly. (In the same way that a new test score lower than your current cumulative grade always must pull that grade downward.) Answer: <math>\boxed{\text<ins class="diffchange diffchange-inline">{\textbf</ins>{(A)<ins class="diffchange diffchange-inline">}</ins>}}</math>.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 7==</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 7==</div></td></tr>
</table>
Ashwin.s
https://artofproblemsolving.com/wiki/index.php?title=2018_AMC_10A_Problems/Problem_14&diff=200353&oldid=prev
Ashwin.s: /* Solution 6 (eyeball it) */
2023-10-27T15:59:07Z
<p><span dir="auto"><span class="autocomment">Solution 6 (eyeball it)</span></span></p>
<table class="diff diff-contentalign-left" data-mw="interface">
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<col class="diff-marker" />
<col class="diff-content" />
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<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">← Older revision</td>
<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">Revision as of 15:59, 27 October 2023</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l56" >Line 56:</td>
<td colspan="2" class="diff-lineno">Line 56:</td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>A faster solution. Recognize that for exponents of this size <math>3^{n}</math> will be enormously greater than <math>2^{n}</math>, so the terms involving <math>2</math> will actually have very little effect on the quotient. Now we know the answer will be very close to <math>81</math>.</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>A faster solution. Recognize that for exponents of this size <math>3^{n}</math> will be enormously greater than <math>2^{n}</math>, so the terms involving <math>2</math> will actually have very little effect on the quotient. Now we know the answer will be very close to <math>81</math>.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'>−</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>Notice that the terms being added on to the top and bottom are in the ratio <math>\frac{1}{16}</math> with each other, so they must pull the ratio down from 81 very slightly. (In the same way that a new test score lower than your current cumulative grade always must pull that grade downward.) Answer: <math>\boxed{(A)}</math>.</div></td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>Notice that the terms being added on to the top and bottom are in the ratio <math>\frac{1}{16}</math> with each other, so they must pull the ratio down from 81 very slightly. (In the same way that a new test score lower than your current cumulative grade always must pull that grade downward.) Answer: <math>\boxed<ins class="diffchange diffchange-inline">{\text</ins>{(A)<ins class="diffchange diffchange-inline">}</ins>}</math>.</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 7==</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 7==</div></td></tr>
</table>
Ashwin.s
https://artofproblemsolving.com/wiki/index.php?title=2018_AMC_10A_Problems/Problem_14&diff=195207&oldid=prev
Thestudyofeverything: /* Solution 14 (Factoring) */
2023-07-03T19:11:57Z
<p><span dir="auto"><span class="autocomment">Solution 14 (Factoring)</span></span></p>
<table class="diff diff-contentalign-left" data-mw="interface">
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<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">← Older revision</td>
<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">Revision as of 19:11, 3 July 2023</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l121" >Line 121:</td>
<td colspan="2" class="diff-lineno">Line 121:</td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>~andy_lee</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>~andy_lee</div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;"></ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;">==Video Solution (HOW TO THINK CREATIVELY!)==</ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;">https://youtu.be/zb0AcwIDqdg</ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;"></ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;">~Education, the Study of Everything</ins></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==See Also==</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==See Also==</div></td></tr>
</table>
Thestudyofeverything
https://artofproblemsolving.com/wiki/index.php?title=2018_AMC_10A_Problems/Problem_14&diff=179335&oldid=prev
Andy lee: /* Solution 14 (Factoring) */
2022-10-22T21:53:03Z
<p><span dir="auto"><span class="autocomment">Solution 14 (Factoring)</span></span></p>
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<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">← Older revision</td>
<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">Revision as of 21:53, 22 October 2022</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l118" >Line 118:</td>
<td colspan="2" class="diff-lineno">Line 118:</td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 14 (Factoring)==</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 14 (Factoring)==</div></td></tr>
<tr><td class='diff-marker'>−</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>If you factor out <math>3^{100}</math> from the numerator and <math>3^{96}</math> from the denominator, you will get <math>\frac{3^{100}\left(1+(\frac{2}{3}\right)^{100})}{3^{96}\left(1+(\frac{2}{3}\right)^{96})}</math>. Divide the numerator and denominator by <math>3^{96}</math> to get <math>\frac{81\left(1+(\frac{2}{3}\right)^{100})}{\left(1+(\frac{2}{3}\right)^{96})}</math>. We see that every time we multiply <math>\frac{2}{3}</math> by itself, it slightly decreases, so <math>1+(\frac{<del class="diffchange diffchange-inline">3</del>}{<del class="diffchange diffchange-inline">2</del>})^{100}</math> will be ever so slightly smaller than <math>1+(\frac{2}{3})^{96}</math>. Thus, the decimal representation of <math>\frac{\left(1+(\frac{2}{3}\right)^{100})}{\left(1+(\frac{2}{3}\right)^{96})}</math> will be extremely close to <math>1</math>, so our solution will be the largest integer that is less than <math>81</math>. Thus, the answer is <math>\boxed{\text{(A)} \ 80}.</math>  </div></td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>If you factor out <math>3^{100}</math> from the numerator and <math>3^{96}</math> from the denominator, you will get <math>\frac{3^{100}\left(1+(\frac{2}{3}\right)^{100})}{3^{96}\left(1+(\frac{2}{3}\right)^{96})}</math>. Divide the numerator and denominator by <math>3^{96}</math> to get <math>\frac{81\left(1+(\frac{2}{3}\right)^{100})}{\left(1+(\frac{2}{3}\right)^{96})}</math>. We see that every time we multiply <math>\frac{2}{3}</math> by itself, it slightly decreases, so <math>1+(\frac{<ins class="diffchange diffchange-inline">2</ins>}{<ins class="diffchange diffchange-inline">3</ins>})^{100}</math> will be ever so slightly smaller than <math>1+(\frac{2}{3})^{96}</math>. Thus, the decimal representation of <math>\frac{\left(1+(\frac{2}{3}\right)^{100})}{\left(1+(\frac{2}{3}\right)^{96})}</math> will be extremely close to <math>1</math>, so our solution will be the largest integer that is less than <math>81</math>. Thus, the answer is <math>\boxed{\text{(A)} \ 80}.</math>  </div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>~andy_lee</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>~andy_lee</div></td></tr>
</table>
Andy lee
https://artofproblemsolving.com/wiki/index.php?title=2018_AMC_10A_Problems/Problem_14&diff=179334&oldid=prev
Andy lee: /* Solution 14 (Factoring) */
2022-10-22T21:52:26Z
<p><span dir="auto"><span class="autocomment">Solution 14 (Factoring)</span></span></p>
<table class="diff diff-contentalign-left" data-mw="interface">
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<col class="diff-marker" />
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<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">← Older revision</td>
<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">Revision as of 21:52, 22 October 2022</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l118" >Line 118:</td>
<td colspan="2" class="diff-lineno">Line 118:</td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 14 (Factoring)==</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 14 (Factoring)==</div></td></tr>
<tr><td class='diff-marker'>−</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>If you factor out <math>3^{100}</math> from the numerator and <math>3^{96}</math> from the denominator, you will get <math>\frac{3^{100}\left(1+(\frac{<del class="diffchange diffchange-inline">3</del>}{<del class="diffchange diffchange-inline">2</del>}\right)^{100})}{3^{96}\left(1+(\frac{<del class="diffchange diffchange-inline">3</del>}{<del class="diffchange diffchange-inline">2</del>}\right)^{96})}</math>. Divide the numerator and denominator by <math>3^{96}</math> to get <math>\frac{81\left(1+(\frac{<del class="diffchange diffchange-inline">3</del>}{<del class="diffchange diffchange-inline">2</del>}\right)^{100})}{\left(1+(\frac{<del class="diffchange diffchange-inline">3</del>}{<del class="diffchange diffchange-inline">2</del>}\right)^{96})}</math>. We see that every time we multiply <math>\frac{<del class="diffchange diffchange-inline">3</del>}{<del class="diffchange diffchange-inline">2</del>}</math> by itself, it slightly decreases, so <math>1+(\frac{3}{2})^{100}</math> will be ever so slightly smaller than <math>1+(\frac{<del class="diffchange diffchange-inline">3</del>}{<del class="diffchange diffchange-inline">2</del>})^{96}</math>. Thus, the decimal representation of <math>\frac{\left(1+(\frac{<del class="diffchange diffchange-inline">3</del>}{<del class="diffchange diffchange-inline">2</del>}\right)^{100})}{\left(1+(\frac{<del class="diffchange diffchange-inline">3</del>}{<del class="diffchange diffchange-inline">2</del>}\right)^{96})}</math> will be extremely close to <math>1</math>, so our solution will be the largest integer that is less than <math>81</math>. Thus, the answer is <math>\boxed{\text{(A)} \ 80}.</math>  </div></td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>If you factor out <math>3^{100}</math> from the numerator and <math>3^{96}</math> from the denominator, you will get <math>\frac{3^{100}\left(1+(\frac{<ins class="diffchange diffchange-inline">2</ins>}{<ins class="diffchange diffchange-inline">3</ins>}\right)^{100})}{3^{96}\left(1+(\frac{<ins class="diffchange diffchange-inline">2</ins>}{<ins class="diffchange diffchange-inline">3</ins>}\right)^{96})}</math>. Divide the numerator and denominator by <math>3^{96}</math> to get <math>\frac{81\left(1+(\frac{<ins class="diffchange diffchange-inline">2</ins>}{<ins class="diffchange diffchange-inline">3</ins>}\right)^{100})}{\left(1+(\frac{<ins class="diffchange diffchange-inline">2</ins>}{<ins class="diffchange diffchange-inline">3</ins>}\right)^{96})}</math>. We see that every time we multiply <math>\frac{<ins class="diffchange diffchange-inline">2</ins>}{<ins class="diffchange diffchange-inline">3</ins>}</math> by itself, it slightly decreases, so <math>1+(\frac{3}{2})^{100}</math> will be ever so slightly smaller than <math>1+(\frac{<ins class="diffchange diffchange-inline">2</ins>}{<ins class="diffchange diffchange-inline">3</ins>})^{96}</math>. Thus, the decimal representation of <math>\frac{\left(1+(\frac{<ins class="diffchange diffchange-inline">2</ins>}{<ins class="diffchange diffchange-inline">3</ins>}\right)^{100})}{\left(1+(\frac{<ins class="diffchange diffchange-inline">2</ins>}{<ins class="diffchange diffchange-inline">3</ins>}\right)^{96})}</math> will be extremely close to <math>1</math>, so our solution will be the largest integer that is less than <math>81</math>. Thus, the answer is <math>\boxed{\text{(A)} \ 80}.</math>  </div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>~andy_lee</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>~andy_lee</div></td></tr>
</table>
Andy lee
https://artofproblemsolving.com/wiki/index.php?title=2018_AMC_10A_Problems/Problem_14&diff=179324&oldid=prev
Andy lee: /* Solution 14 (Factoring) */
2022-10-22T19:54:12Z
<p><span dir="auto"><span class="autocomment">Solution 14 (Factoring)</span></span></p>
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<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">← Older revision</td>
<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">Revision as of 19:54, 22 October 2022</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l118" >Line 118:</td>
<td colspan="2" class="diff-lineno">Line 118:</td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 14 (Factoring)==</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 14 (Factoring)==</div></td></tr>
<tr><td class='diff-marker'>−</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>If you factor out <math>3^{100}</math> from the <del class="diffchange diffchange-inline">top </del>and <math>3^{96}</math> from the <del class="diffchange diffchange-inline">bottom</del>, you will get <math>\frac{3^{100}\left(1+(\frac{3}{2}\right)^{100})}{3^{96}\left(1+(\frac{3}{2}\right)^{96})}</math>. Divide the numerator and denominator by <math>3^{96}</math> to get <math>\frac{81\left(1+(\frac{3}{2}\right)^{100})}{\left(1+(\frac{3}{2}\right)^{96})}</math>. We see that every time we multiply <math>\frac{3}{2}</math> by itself, it slightly decreases, so <math>1+(\frac{3}{2})^{100}</math> will be ever so slightly smaller than <math>1+(\frac{3}{2})^{96}</math>. Thus, the decimal representation of <math>\frac{\left(1+(\frac{3}{2}\right)^{100})}{\left(1+(\frac{3}{2}\right)^{96})}</math> will be extremely close to <math>1</math>, so our solution will be the largest integer that is less than <math>81</math>. Thus, the answer is <math>\boxed{\text{(A)} \ 80}.</math>  </div></td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>If you factor out <math>3^{100}</math> from the <ins class="diffchange diffchange-inline">numerator </ins>and <math>3^{96}</math> from the <ins class="diffchange diffchange-inline">denominator</ins>, you will get <math>\frac{3^{100}\left(1+(\frac{3}{2}\right)^{100})}{3^{96}\left(1+(\frac{3}{2}\right)^{96})}</math>. Divide the numerator and denominator by <math>3^{96}</math> to get <math>\frac{81\left(1+(\frac{3}{2}\right)^{100})}{\left(1+(\frac{3}{2}\right)^{96})}</math>. We see that every time we multiply <math>\frac{3}{2}</math> by itself, it slightly decreases, so <math>1+(\frac{3}{2})^{100}</math> will be ever so slightly smaller than <math>1+(\frac{3}{2})^{96}</math>. Thus, the decimal representation of <math>\frac{\left(1+(\frac{3}{2}\right)^{100})}{\left(1+(\frac{3}{2}\right)^{96})}</math> will be extremely close to <math>1</math>, so our solution will be the largest integer that is less than <math>81</math>. Thus, the answer is <math>\boxed{\text{(A)} \ 80}.</math>  </div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>~andy_lee</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>~andy_lee</div></td></tr>
</table>
Andy lee
https://artofproblemsolving.com/wiki/index.php?title=2018_AMC_10A_Problems/Problem_14&diff=179323&oldid=prev
Andy lee at 19:53, 22 October 2022
2022-10-22T19:53:46Z
<p></p>
<table class="diff diff-contentalign-left" data-mw="interface">
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<col class="diff-content" />
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<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">← Older revision</td>
<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">Revision as of 19:53, 22 October 2022</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l116" >Line 116:</td>
<td colspan="2" class="diff-lineno">Line 116:</td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>~ Zeeshan12 [Now there's 13 :) ]</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>~ Zeeshan12 [Now there's 13 :) ]</div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;"></ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;">==Solution 14 (Factoring)==</ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;">If you factor out <math>3^{100}</math> from the top and <math>3^{96}</math> from the bottom, you will get <math>\frac{3^{100}\left(1+(\frac{3}{2}\right)^{100})}{3^{96}\left(1+(\frac{3}{2}\right)^{96})}</math>. Divide the numerator and denominator by <math>3^{96}</math> to get <math>\frac{81\left(1+(\frac{3}{2}\right)^{100})}{\left(1+(\frac{3}{2}\right)^{96})}</math>. We see that every time we multiply <math>\frac{3}{2}</math> by itself, it slightly decreases, so <math>1+(\frac{3}{2})^{100}</math> will be ever so slightly smaller than <math>1+(\frac{3}{2})^{96}</math>. Thus, the decimal representation of <math>\frac{\left(1+(\frac{3}{2}\right)^{100})}{\left(1+(\frac{3}{2}\right)^{96})}</math> will be extremely close to <math>1</math>, so our solution will be the largest integer that is less than <math>81</math>. Thus, the answer is <math>\boxed{\text{(A)} \ 80}.</math> </ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;"></ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;">~andy_lee</ins></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==See Also==</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==See Also==</div></td></tr>
</table>
Andy lee
https://artofproblemsolving.com/wiki/index.php?title=2018_AMC_10A_Problems/Problem_14&diff=176698&oldid=prev
Turtle09: /* Solution 6 (eyeball it) */
2022-08-05T21:24:46Z
<p><span dir="auto"><span class="autocomment">Solution 6 (eyeball it)</span></span></p>
<table class="diff diff-contentalign-left" data-mw="interface">
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<col class="diff-marker" />
<col class="diff-content" />
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<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">← Older revision</td>
<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">Revision as of 21:24, 5 August 2022</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l57" >Line 57:</td>
<td colspan="2" class="diff-lineno">Line 57:</td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>Notice that the terms being added on to the top and bottom are in the ratio <math>\frac{1}{16}</math> with each other, so they must pull the ratio down from 81 very slightly. (In the same way that a new test score lower than your current cumulative grade always must pull that grade downward.) Answer: <math>\boxed{(A)}</math>.</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>Notice that the terms being added on to the top and bottom are in the ratio <math>\frac{1}{16}</math> with each other, so they must pull the ratio down from 81 very slightly. (In the same way that a new test score lower than your current cumulative grade always must pull that grade downward.) Answer: <math>\boxed{(A)}</math>.</div></td></tr>
<tr><td class='diff-marker'>−</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div><del style="font-weight: bold; text-decoration: none;"></del></div></td><td colspan="2"> </td></tr>
<tr><td class='diff-marker'>−</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div><del style="font-weight: bold; text-decoration: none;">Same - megahertz13</del></div></td><td colspan="2"> </td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 7==</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 7==</div></td></tr>
</table>
Turtle09
https://artofproblemsolving.com/wiki/index.php?title=2018_AMC_10A_Problems/Problem_14&diff=174874&oldid=prev
Megahertz13: /* Solution 6 (eyeball it) */
2022-06-14T18:51:22Z
<p><span dir="auto"><span class="autocomment">Solution 6 (eyeball it)</span></span></p>
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<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">← Older revision</td>
<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">Revision as of 18:51, 14 June 2022</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l57" >Line 57:</td>
<td colspan="2" class="diff-lineno">Line 57:</td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>Notice that the terms being added on to the top and bottom are in the ratio <math>\frac{1}{16}</math> with each other, so they must pull the ratio down from 81 very slightly. (In the same way that a new test score lower than your current cumulative grade always must pull that grade downward.) Answer: <math>\boxed{(A)}</math>.</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>Notice that the terms being added on to the top and bottom are in the ratio <math>\frac{1}{16}</math> with each other, so they must pull the ratio down from 81 very slightly. (In the same way that a new test score lower than your current cumulative grade always must pull that grade downward.) Answer: <math>\boxed{(A)}</math>.</div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;"></ins></div></td></tr>
<tr><td colspan="2"> </td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><ins style="font-weight: bold; text-decoration: none;">Same - megahertz13</ins></div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 7==</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 7==</div></td></tr>
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Megahertz13
https://artofproblemsolving.com/wiki/index.php?title=2018_AMC_10A_Problems/Problem_14&diff=174111&oldid=prev
Zeeshan12: /* Solution 13 (slightly similar to Solution 7) */
2022-05-29T22:46:24Z
<p><span dir="auto"><span class="autocomment">Solution 13 (slightly similar to Solution 7)</span></span></p>
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<td colspan="2" style="background-color: #fff; color: #222; text-align: center;">Revision as of 22:46, 29 May 2022</td>
</tr><tr><td colspan="2" class="diff-lineno" id="mw-diff-left-l113" >Line 113:</td>
<td colspan="2" class="diff-lineno">Line 113:</td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 13 (slightly similar to Solution 7)==</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>==Solution 13 (slightly similar to Solution 7)==</div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'>−</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div>If you multiply <math>(3^{96} + 2^{96})</math> by <math>(3^{4} + 2^{4})</math> (to get the exponent up to 100), you'll get <math>(3^{100} + 2^{100}) + 3^{96} \cdot 2^{4} + 2^{96} \cdot 3^{4}</math>. Thus, in the numerator, if you add and subtract by <math>3^{96} \cdot 2^{4}</math> and <math>2^{96} \cdot 3^{4}</math>, you'll get <math>\frac{(3^{4} + 2^{4})(3^{100} + 2^{100}) - 3^{96} \cdot 2^{4} - 2^{96} \cdot 3^{4}}{3^{96}+2^{96}}</math>. You can then take out out the first number to get <math>3^{4} + 2^{4} - \frac{3^{96} \cdot 2^{4} + 2^{96} \cdot 3^{4}}{3^{96}+2^{96}}</math>. This can then be written as <math>87 - \frac{16 \cdot 3^{96} + 16 \cdot 2^{96} + 75 \cdot 2^{96}}{3^{96}+2^{96}}</math>, factoring out the 16 and splitting the fraction will give you <math>87 - 16 - \frac{<del class="diffchange diffchange-inline">75 </del>\cdot 2^{96}}{3^{96}+2^{96}}</math>, giving you <math>81 - \frac{65 \cdot 2^{96}}{3^{96}+2^{96}}</math>. While you can roughly say that <math>\frac{<del class="diffchange diffchange-inline">75 </del>\cdot 2^{96}}{3^{96}+2^{96}} < 1</math> you can also notice that the only answer choice less than 81 is 80, thus the answer is <math>\boxed{\text{(A)} \ 80}.</math>  </div></td><td class='diff-marker'>+</td><td style="color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div>If you multiply <math>(3^{96} + 2^{96})</math> by <math>(3^{4} + 2^{4})</math> (to get the exponent up to 100), you'll get <math>(3^{100} + 2^{100}) + 3^{96} \cdot 2^{4} + 2^{96} \cdot 3^{4}</math>. Thus, in the numerator, if you add and subtract by <math>3^{96} \cdot 2^{4}</math> and <math>2^{96} \cdot 3^{4}</math>, you'll get <math>\frac{(3^{4} + 2^{4})(3^{100} + 2^{100}) - 3^{96} \cdot 2^{4} - 2^{96} \cdot 3^{4}}{3^{96}+2^{96}}</math>. You can then take out out the first number to get <math>3^{4} + 2^{4} - \frac{3^{96} \cdot 2^{4} + 2^{96} \cdot 3^{4}}{3^{96}+2^{96}}</math>. This can then be written as <math>87 - \frac{16 \cdot 3^{96} + 16 \cdot 2^{96} + 75 \cdot 2^{96}}{3^{96}+2^{96}}</math>, factoring out the 16 and splitting the fraction will give you <math>87 - 16 - \frac{<ins class="diffchange diffchange-inline">65 </ins>\cdot 2^{96}}{3^{96}+2^{96}}</math>, giving you <math>81 - \frac{65 \cdot 2^{96}}{3^{96}+2^{96}}</math>. While you can roughly say that <math>\frac{<ins class="diffchange diffchange-inline">65 </ins>\cdot 2^{96}}{3^{96}+2^{96}} < 1</math> you can also notice that the only answer choice less than 81 is 80, thus the answer is <math>\boxed{\text{(A)} \ 80}.</math>  </div></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"></td></tr>
<tr><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>~ Zeeshan12 [Now there's 13 :) ]</div></td><td class='diff-marker'> </td><td style="background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;"><div>~ Zeeshan12 [Now there's 13 :) ]</div></td></tr>
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Zeeshan12