Difference between revisions of "2018 AMC 10A Problems/Problem 8"

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==Solution==
 
==Solution==
Let <math>x</math> be the number of 5-cent stamps that Joe has. Therefore, he must have <math>x+3</math> 10-cent stamps and <math>23-(x+3)-x</math> 25-cent stamps. Since the toal value of his collection is 320 cents, we can write
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Let <math>x</math> be the number of 5-cent stamps that Joe has. Therefore, he must have <math>(x+3)</math> 10-cent stamps and <math>(23-(x+3)-x)</math> 25-cent stamps. Since the toal value of his collection is 320 cents, we can write
 
<cmath>5x+10(x+3)+25(23-(x+3)-x)=320 \Rightarrow 5x+10(x+3)+25(20-2x)=320 \Rightarrow 5x+10x+30+500-50x=320 \Rightarrow 35x=210 \Rightarrow x=6</cmath>  
 
<cmath>5x+10(x+3)+25(23-(x+3)-x)=320 \Rightarrow 5x+10(x+3)+25(20-2x)=320 \Rightarrow 5x+10x+30+500-50x=320 \Rightarrow 35x=210 \Rightarrow x=6</cmath>  
 
Joe has 6 5-cent stamps, 9 10-cent stamps, and 8 25-cent stamps. Thus, our answer is  
 
Joe has 6 5-cent stamps, 9 10-cent stamps, and 8 25-cent stamps. Thus, our answer is  

Revision as of 17:10, 8 February 2018

Joe has a collection of 23 coins, consisting of 5-cent coins, 10-cent coins, and 25-cent coins. He has 3 more 10-cent coins than 5-cent coins, and the total value of his collection is 320 cents. How many more 25-cent coins does Joe have than 5-cent coins?

$\textbf{(A) }   0   \qquad        \textbf{(B) }   1   \qquad    \textbf{(C) }   2   \qquad   \textbf{(D) }  3  \qquad  \textbf{(E) }   4$

Solution

Let $x$ be the number of 5-cent stamps that Joe has. Therefore, he must have $(x+3)$ 10-cent stamps and $(23-(x+3)-x)$ 25-cent stamps. Since the toal value of his collection is 320 cents, we can write \[5x+10(x+3)+25(23-(x+3)-x)=320 \Rightarrow 5x+10(x+3)+25(20-2x)=320 \Rightarrow 5x+10x+30+500-50x=320 \Rightarrow 35x=210 \Rightarrow x=6\] Joe has 6 5-cent stamps, 9 10-cent stamps, and 8 25-cent stamps. Thus, our answer is $8-6=\boxed{2}$

~Nivek

See Also

2018 AMC 10A (ProblemsAnswer KeyResources)
Preceded by
Problem 7
Followed by
Problem 9
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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