# 2018 AMC 10A Problems/Problem 8

Joe has a collection of 23 coins, consisting of 5-cent coins, 10-cent coins, and 25-cent coins. He has 3 more 10-cent coins than 5-cent coins, and the total value of his collection is 320 cents. How many more 25-cent coins does Joe have than 5-cent coins?

$\textbf{(A) } 0 \qquad \textbf{(B) } 1 \qquad \textbf{(C) } 2 \qquad \textbf{(D) } 3 \qquad \textbf{(E) } 4$

## Solution

Let $x$ be the number of 5-cent stamps that Joe has. Therefore, he must have $x+3$ 10-cent stamps and $23-(x+3)-x$ 25-cent stamps. Since the toal value of his collection is 320 cents, we can write \begin{*align} 5x+10(x+3)+25(23-(x+3)-x) &=320 \\ 5x+10(x+3)+25(20-2x) &=320 \\ 5x+10x+30+500-50x &=320 \\ 35x & =210 \\ x=6 \ \end{*align} Joe has 6 5-cent stamps, 9 10-cent stamps, and 8 25-cent stamps. Thus, our answer is $8-6=\boxed{2}$

~Nivek

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