Difference between revisions of "2018 AMC 10B Problems/Problem 1"

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-{{duplicate|[[2018 AMC 12B Problems|2018 AMC 12B #1]] and [[2018 AMC 10B Problems|2018 AMC 10B #1]]}}
-==Problem==
-Kate bakes a <math>20</math>-inch by <math>18</math>-inch pan of cornbread. The cornbread is cut into pieces that measure <math>2</math> inches by <math>2</math> inches. How many pieces of cornbread does the pan contain?
-<math>\textbf{(A) } 90 \qquad \textbf{(B) } 100 \qquad \textbf{(C) } 180 \qquad \textbf{(D) } 200 \qquad \textbf{(E) } 360</math>
-== Solution 1 ==
-The area of the pan is <math>20\cdot18=360</math>. Since the area of each piece is <math>2\cdot2=4</math>, there are <math>\frac{360}{4} = \boxed{\textbf{(A) } 90}</math> pieces.
-== Solution 2 ==
-By dividing each of the dimensions by <math>2</math>, we get a <math>10\times9</math> grid that makes <math>\boxed{\textbf{(A) } 90}</math> pieces.
-==Video Solution==
-https://youtu.be/o5MUHOmF1zo
-~savannahsolver
-==See Also==
-{{AMC10 box|year=2018|ab=B|before=First Problem|num-a=2}}
-{{AMC12 box|year=2018|ab=B|before=First Problem|num-a=2}}
-{{MAA Notice}}

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