Difference between revisions of "2018 AMC 10B Problems/Problem 1"

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By dividing the each of the dimensions by <math>2</math>, we get a <math>10\times9</math> grid which makes <math>90</math> pieces. Thus, the answer is <math>\boxed{A}</math>.
 
By dividing the each of the dimensions by <math>2</math>, we get a <math>10\times9</math> grid which makes <math>90</math> pieces. Thus, the answer is <math>\boxed{A}</math>.
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==See Also==
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{{AMC10 box|year=2018|ab=B|before=First Problem|num-a=2}}
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{{AMC12 box|year=2018|ab=B|before=First Problem|num-a=2}}
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{{MAA Notice}}

Revision as of 14:59, 16 February 2018

Kate bakes 20-inch by 18-inch pan of cornbread. The cornbread is cut into pieces that measure 2 inches by 2 inches. How many pieces of cornbread does the pan contain?

$\textbf{(A) } 90 \qquad \textbf{(B) } 100 \qquad \textbf{(C) } 180 \qquad \textbf{(D) } 200 \qquad \textbf{(E) } 360$

Solution 1

The area of the pan is $20\cdot18$ = $360$. Since the area of each piece is $4$, there are 360/40 = 90 pieces. Thus, the answer is $\boxed{A}$.

Solution 2

By dividing the each of the dimensions by $2$, we get a $10\times9$ grid which makes $90$ pieces. Thus, the answer is $\boxed{A}$.

See Also

2018 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions
2018 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

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