Difference between revisions of "2018 AMC 12B Problems/Problem 13"

(Redirected page to 2018 AMC 10B Problems/Problem 15)
 
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#REDIRECT[[2018 AMC 10B Problems/Problem 15]]
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==Problem==
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Square <math>ABCD</math> has side length <math>30</math>. Point <math>P</math> lies inside the square so that <math>AP = 12</math> and <math>BP = 26</math>. The centroids of <math>\triangle{ABP}</math>, <math>\triangle{BCP}</math>, <math>\triangle{CDP}</math>, and <math>\triangle{DAP}</math> are the vertices of a convex quadrilateral. What is the area of that quadrilateral?
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<asy>
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unitsize(120);
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pair B = (0, 0), A = (0, 1), D = (1, 1), C = (1, 0), P = (1/4, 2/3);
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draw(A--B--C--D--cycle);
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dot(P);
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defaultpen(fontsize(10pt));
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draw(A--P--B);
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draw(C--P--D);
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label("$A$", A, W);
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label("$B$", B, W);
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label("$C$", C, E);
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label("$D$", D, E);
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label("$P$", P, N*1.5+E*0.5);
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dot(A);
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dot(B);
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dot(C);
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dot(D);
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</asy>
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<math>\textbf{(A) }100\sqrt{2}\qquad\textbf{(B) }100\sqrt{3}\qquad\textbf{(C) }200\qquad\textbf{(D) }200\sqrt{2}\qquad\textbf{(E) }200\sqrt{3}</math>[/quote]
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==Solution==

Revision as of 18:50, 16 February 2018

Problem

Square $ABCD$ has side length $30$. Point $P$ lies inside the square so that $AP = 12$ and $BP = 26$. The centroids of $\triangle{ABP}$, $\triangle{BCP}$, $\triangle{CDP}$, and $\triangle{DAP}$ are the vertices of a convex quadrilateral. What is the area of that quadrilateral?

[asy] unitsize(120); pair B = (0, 0), A = (0, 1), D = (1, 1), C = (1, 0), P = (1/4, 2/3); draw(A--B--C--D--cycle); dot(P); defaultpen(fontsize(10pt)); draw(A--P--B); draw(C--P--D); label("$A$", A, W); label("$B$", B, W); label("$C$", C, E); label("$D$", D, E); label("$P$", P, N*1.5+E*0.5); dot(A); dot(B); dot(C); dot(D); [/asy]


$\textbf{(A) }100\sqrt{2}\qquad\textbf{(B) }100\sqrt{3}\qquad\textbf{(C) }200\qquad\textbf{(D) }200\sqrt{2}\qquad\textbf{(E) }200\sqrt{3}$[/quote]

Solution