Difference between revisions of "2018 AMC 12B Problems/Problem 6"
Giraffefun (talk | contribs) (Created page with "==Problem== ==Solution== ==Also See==") |
m (→Solution 1) |
||
(5 intermediate revisions by one other user not shown) | |||
Line 1: | Line 1: | ||
==Problem== | ==Problem== | ||
− | + | Suppose <math>S</math> cans of soda can be purchased from a vending machine for <math>Q</math> quarters. Which of the following expressions describes the number of cans of soda that can be purchased for <math>D</math> dollars, where 1 dollar is worth 4 quarters? | |
− | ==Also | + | <math>\textbf{(A)} \frac{4DQ}{S} \qquad \textbf{(B)} \frac{4DS}{Q} \qquad \textbf{(C)} \frac{4Q}{DS} \qquad \textbf{(D)} \frac{DQ}{4S} \qquad \textbf{(E)} \frac{DS}{4Q}</math> |
+ | |||
+ | ==Solution 1== | ||
+ | The unit price for a can of soda (in quarters) is <math>\frac{S}{Q}</math>. Thus, the number of cans which can be bought for <math>D</math> dollars (<math>4D</math> quarters) is<math> \boxed {\textbf{(B)} \frac{4DS}{Q}}</math> | ||
+ | |||
+ | ==See Also== | ||
+ | {{AMC12 box|year=2018|ab=B|num-b=5|num-a=7}} | ||
+ | {{MAA Notice}} |
Revision as of 02:08, 19 February 2018
Problem
Suppose cans of soda can be purchased from a vending machine for quarters. Which of the following expressions describes the number of cans of soda that can be purchased for dollars, where 1 dollar is worth 4 quarters?
Solution 1
The unit price for a can of soda (in quarters) is . Thus, the number of cans which can be bought for dollars ( quarters) is
See Also
2018 AMC 12B (Problems • Answer Key • Resources) | |
Preceded by Problem 5 |
Followed by Problem 7 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.