Difference between revisions of "2018 AMC 8 Problems/Problem 3"
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Arn counts <math>7</math> (assuming they start at <math>1</math>) so he leaves first. Then Cyd counts <math>14</math>, as there are <math>7</math> numbers to be counted from this point. Then Fon, Bob, Eve, so last one standing is Dan, <math>\textbf{(D)}</math> -scrabbler94 | Arn counts <math>7</math> (assuming they start at <math>1</math>) so he leaves first. Then Cyd counts <math>14</math>, as there are <math>7</math> numbers to be counted from this point. Then Fon, Bob, Eve, so last one standing is Dan, <math>\textbf{(D)}</math> -scrabbler94 | ||
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==See Also== | ==See Also== | ||
{{AMC8 box|year=2018|num-b=2|num-a=4}} | {{AMC8 box|year=2018|num-b=2|num-a=4}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 14:32, 21 November 2018
Problem 3
Students Arn, Bob, Cyd, Dan, Eve, and Fon are arranged in that order in a circle. They start counting: Arn first, then Bob, and so forth. When the number contains a 7 as a digit (such as 47) or is a multiple of 7 that person leaves the circle and the counting continues. Who is the last one present in the circle?
Solution
The five numbers which cause people to leave the circle are 
and 
Arn counts 
(assuming they start at 
) so he leaves first. Then Cyd counts 
, as there are numbers to be counted from this point. Then Fon, Bob, Eve, so last one standing is Dan, 
-scrabbler94
See Also
| 2018 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 2 |
Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
