Difference between revisions of "2019 AIME I Problems/Problem 1"

(Problem 1)
Line 1: Line 1:
 
==Problem 1==
 
==Problem 1==
 
What is the sum of the digits of <math>9+99+999+...+99..99</math>  (321 9's)?
 
What is the sum of the digits of <math>9+99+999+...+99..99</math>  (321 9's)?
 +
 +
==Solution==
  
 
{{AIME box|year=2019|n=I|before=First Problem|num-a=2}}
 
{{AIME box|year=2019|n=I|before=First Problem|num-a=2}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 22:21, 14 March 2019

Problem 1

What is the sum of the digits of $9+99+999+...+99..99$ (321 9's)?

Solution

2019 AIME I (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All AIME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

Invalid username
Login to AoPS