Difference between revisions of "2019 AIME I Problems/Problem 8"
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==Problem 8== | ==Problem 8== | ||
| + | Let <math>x</math> be a real number such that <math>\sin^{10}x+\cos^{10} x = \tfrac{11}{36}</math>. Then <math>\sin^{12}x+\cos^{12} x = \tfrac{m}{n}</math> where <math>m</math> and <math>n</math> are relatively prime positive integers. Find <math>m+n</math>. | ||
==Solution== | ==Solution== | ||
Revision as of 20:33, 14 March 2019
The 2019 AIME I takes place on March 13, 2019.
Contents
Problem 8
Let 
be a real number such that 
. Then 
where 
and 
are relatively prime positive integers. Find 
.
Solution
NOT ALLOWED!
Solution 2
Can't do that!
See Also
| 2019 AIME I (Problems • Answer Key • Resources) | ||
| Preceded by Problem 7 |
Followed by Problem 9 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
| All AIME Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
