Difference between revisions of "2019 AMC 8 Problems/Problem 11"
(→Solution 4) |
|||
(9 intermediate revisions by 8 users not shown) | |||
Line 11: | Line 11: | ||
Solving gives us <math>x = 31</math>. | Solving gives us <math>x = 31</math>. | ||
− | But we want the number of students taking only a math class | + | But we want the number of students taking only a math class, |
− | + | which is <math>70 - 31 = 39</math>. | |
<math>\boxed{\textbf{(D)}\ 39}</math> | <math>\boxed{\textbf{(D)}\ 39}</math> | ||
Line 20: | Line 20: | ||
==Solution 2== | ==Solution 2== | ||
− | We have <math>70 + 54 = 124</math> people taking classes. However we over-counted the number of people who take both classes. If we subtract the original amount of people who take classes we get that <math>31</math> people took the two classes. To find the amount of people who took only math class | + | We have <math>70 + 54 = 124</math> people taking classes. However, we over-counted the number of people who take both classes. If we subtract the original amount of people who take classes we get that <math>31</math> people took the two classes. To find the amount of people who took only math class, we subtract the people who didn't take only one math class, so we get <math>70 - 31 = \boxed{\textbf{D} \, 39}</math>. |
+ | |||
+ | -fath2012 | ||
==Solution 3== | ==Solution 3== | ||
Line 44: | Line 46: | ||
==Solution 4== | ==Solution 4== | ||
+ | We are looking for students in math only, which is the complement (exactly the rest of the students) compared to those taking a language class. Since <math>54</math> students take a language (with or without math), we subtract that from the total number of students. Since <math>93-54= 39,</math> our answer is <math>\boxed{D 39}.</math> (It's not necessary to know that <math>70</math> students take math.) | ||
+ | ~hailstone | ||
+ | |||
+ | ==Solution Explained== | ||
+ | https://youtu.be/gOZOCFNXMhE ~ The Learning Royal | ||
+ | |||
+ | ==Solution 5== | ||
Associated video - https://www.youtube.com/watch?v=onPaMTO3dSA | Associated video - https://www.youtube.com/watch?v=onPaMTO3dSA | ||
Line 49: | Line 58: | ||
Solution detailing how to solve the problem: https://www.youtube.com/watch?v=Kanl4ni2y0o&list=PLbhMrFqoXXwmwbk2CWeYOYPRbGtmdPUhL&index=12 | Solution detailing how to solve the problem: https://www.youtube.com/watch?v=Kanl4ni2y0o&list=PLbhMrFqoXXwmwbk2CWeYOYPRbGtmdPUhL&index=12 | ||
+ | |||
+ | ==Video Solution== | ||
+ | https://youtu.be/4E8I-NJYAJY | ||
+ | |||
+ | ~savannahsolver | ||
+ | |||
+ | ==Video Solution (CREATIVE ANALYSIS!!!)== | ||
+ | https://youtu.be/2K2ZUw-l1ek | ||
+ | |||
+ | ~Education, the Study of Everything | ||
+ | |||
+ | ==Video Solution by The Power of Logic(Problem 1 to 25 Full Solution)== | ||
+ | https://youtu.be/Xm4ZGND9WoY | ||
+ | |||
+ | ~Hayabusa1 | ||
==See also== | ==See also== | ||
Line 54: | Line 78: | ||
{{MAA Notice}} | {{MAA Notice}} | ||
+ | |||
+ | [[Category: Introductory Combinatorics Problems]] |
Latest revision as of 09:46, 10 September 2023
Contents
Problem 11
The eighth grade class at Lincoln Middle School has students. Each student takes a math class or a foreign language class or both. There are eighth graders taking a math class, and there are eighth graders taking a foreign language class. How many eighth graders take only a math class and not a foreign language class?
Solution 1
Let be the number of students taking both a math and a foreign language class.
By P-I-E, we get = .
Solving gives us .
But we want the number of students taking only a math class,
which is .
~phoenixfire
Solution 2
We have people taking classes. However, we over-counted the number of people who take both classes. If we subtract the original amount of people who take classes we get that people took the two classes. To find the amount of people who took only math class, we subtract the people who didn't take only one math class, so we get .
-fath2012
Solution 3
We know that the sum of all three areas is So, we have:
We are looking for the number of students in only math. This is . Substituting with , our answer is .
-mathnerdnair
Solution 4
We are looking for students in math only, which is the complement (exactly the rest of the students) compared to those taking a language class. Since students take a language (with or without math), we subtract that from the total number of students. Since our answer is (It's not necessary to know that students take math.) ~hailstone
Solution Explained
https://youtu.be/gOZOCFNXMhE ~ The Learning Royal
Solution 5
Associated video - https://www.youtube.com/watch?v=onPaMTO3dSA
Video Solution
Solution detailing how to solve the problem: https://www.youtube.com/watch?v=Kanl4ni2y0o&list=PLbhMrFqoXXwmwbk2CWeYOYPRbGtmdPUhL&index=12
Video Solution
~savannahsolver
Video Solution (CREATIVE ANALYSIS!!!)
~Education, the Study of Everything
Video Solution by The Power of Logic(Problem 1 to 25 Full Solution)
~Hayabusa1
See also
2019 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 10 |
Followed by Problem 12 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.