Difference between revisions of "2019 AMC 8 Problems/Problem 12"

(Solution 1)
(Solution 1)
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==Solution 1==
 
==Solution 1==
B is on the top, and R is on the side, and G is on the right side. That means that (image 2)W is on the left side. From the Third image, you know that P must be on the bottom since G is sideways. That leaves us with the back, so the back must be A. The front is opposite of the back, so the answer is <math>\boxed{\textbf{(A)}\ R}</math>.~heeeeeeeheeeee
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<math>B</math> is on the top, and <math>R</math> is on the side, and <math>G</math> is on the right side. That means that (image 2)<math>W</math> is on the left side. From the third image, you know that <math>P</math> must be on the bottom since <math>G</math> is sideways. That leaves us with the back, so the back must be <math>A</math>. The front is opposite of the back, so the answer is <math>\boxed{\textbf{(A)}\ R}</math>.~heeeeeeeheeeee
  
 
==Solution 2==
 
==Solution 2==
 
{{AMC8 box|year=2019|num-b=11|num-a=13}}
 
{{AMC8 box|year=2019|num-b=11|num-a=13}}

Revision as of 07:39, 21 November 2019

Problem

The faces of a cube are painted in six different colors: red (R), white (W), green (G), brown (B), aqua (A), and purple (P). Three views of the cube are shown below. What is the color of the face opposite the aqua face?

$A)$ red $B)$ white $C)$ green $D)$ brown $E)$ purple

[img]http://cdn.artofproblemsolving.com/school/crypt/00138-220523a86ffc7b7b501c1ee1e6584ccad58efb8a/files/2019AMC8Prob12.png[/img]

Solution 1

$B$ is on the top, and $R$ is on the side, and $G$ is on the right side. That means that (image 2)$W$ is on the left side. From the third image, you know that $P$ must be on the bottom since $G$ is sideways. That leaves us with the back, so the back must be $A$. The front is opposite of the back, so the answer is $\boxed{\textbf{(A)}\ R}$.~heeeeeeeheeeee

Solution 2

2019 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 11
Followed by
Problem 13
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions