Difference between revisions of "2019 AMC 8 Problems/Problem 16"
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https://youtu.be/5K1AgeZ8rUQ - happytwin | https://youtu.be/5K1AgeZ8rUQ - happytwin | ||
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+ | == Video Solution == | ||
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+ | Solution detailing how to solve the problem: https://www.youtube.com/watch?v=sEZ0sM-d1FA&list=PLbhMrFqoXXwmwbk2CWeYOYPRbGtmdPUhL&index=17 | ||
==See Also== | ==See Also== |
Latest revision as of 14:33, 23 April 2021
Contents
Problem 16
Qiang drives miles at an average speed of miles per hour. How many additional miles will he have to drive at miles per hour to average miles per hour for the entire trip?
Solution 1
The only option that is easily divisible by is . Which gives 2 hours of travel. And by the formula
And =
Thus
Both are equal and thus our answer is
Solution 2
Note that the average speed is simply the total distance over the total time. Let the number of additional miles he has to drive be Therefore, the total distance is and the total time (in hours) is We can set up the following equation: Simplifying the equation, we get Solving the equation yields so our answer is .
Solution 3
If he travels miles at a speed of miles per hour, he travels for 30 min. Average rate is total distance over total time so , where d is the distance left to travel and t is the time to travel that distance. solve for to get . you also know that he has to travel miles per hour for some time, so plug that in for d to get and and since , the answer is .
Video Solution
Associated Video - https://www.youtube.com/watch?v=OC1KdFeZFeE
https://youtu.be/5K1AgeZ8rUQ - happytwin
Video Solution
Solution detailing how to solve the problem: https://www.youtube.com/watch?v=sEZ0sM-d1FA&list=PLbhMrFqoXXwmwbk2CWeYOYPRbGtmdPUhL&index=17
See Also
2019 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 15 |
Followed by Problem 17 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.