Difference between revisions of "2019 AMC 8 Problems/Problem 7"

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==Solution 1==
 
==Solution 1==
 
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Right now, she scored 76, 94, and 87 points, with a total of 257 points. She wants her average to be 81 for her 5 tests so she needs to score 405 points in total. She needs to score a total of (405-257) 148 points in her 2 tests. So the minimum score she can get is when one of her 2 scores is 100. So the least possible score she can get is [A] 48.
  
 
==See Also==
 
==See Also==

Revision as of 12:34, 20 November 2019

Problem 7

Shauna takes five tests, each wort a maximum of $100$ points. Her scores on the first three tests are $76$, $94$, and $87$. In order to average $81$ for all five tests, what is the lowest score she could earn on one of the other two tests?

$\textbf{(A) }48\qquad\textbf{(B) }52\qquad\textbf{(C) }66\qquad\textbf{(D) }70\qquad\textbf{(E) }74$

Solution 1

Right now, she scored 76, 94, and 87 points, with a total of 257 points. She wants her average to be 81 for her 5 tests so she needs to score 405 points in total. She needs to score a total of (405-257) 148 points in her 2 tests. So the minimum score she can get is when one of her 2 scores is 100. So the least possible score she can get is [A] 48.

See Also

2019 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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