Difference between revisions of "2019 AMC 8 Problems/Problem 8"

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(Solution 1)
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==Solution 1==
 
==Solution 1==
After Gilda gives 20% of the marbles to Pedro, she has 80% of the marbles left. If she then gives 10% OF WHATS LEFT to Ebony, she has (0.8*0.9) 72% of what she had at the beginning. Finally, she gives 25% of what's left to her brother, so she has (0.75*0.72){\textbf{(E)}\ 54%}$ of what she had in the beginning left.~heeeeeeeheeeeee
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After Gilda gives 20% of the marbles to Pedro, she has 80% of the marbles left. If she then gives 10% OF WHATS LEFT to Ebony, she has (0.8*0.9) 72% of what she had at the beginning. Finally, she gives 25% of what's left to her brother, so she has (0.75*0.72) <math>\boxed{\textbf{(E)}\ 54}</math>. of what she had in the beginning left.~heeeeeeeheeeeee
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==See Also==
 
==See Also==

Revision as of 12:46, 20 November 2019

Problem 8

Gilda has a bag of marbles. She gives $20\%$ of them to her friend Pedro. Then Gilda gives $10\%$ of what is left to another friend, Ebony. Finally, Gilda gives $25\%$ of what is now left in the bag to her brother Jimmy. What percentage of her original bag of marbles does Gilda have left for herself?

$\textbf{(A) }20\qquad\textbf{(B) }33\frac{1}{3}\qquad\textbf{(C) }38\qquad\textbf{(D) }45\qquad\textbf{(E) }54$

Solution 1

After Gilda gives 20% of the marbles to Pedro, she has 80% of the marbles left. If she then gives 10% OF WHATS LEFT to Ebony, she has (0.8*0.9) 72% of what she had at the beginning. Finally, she gives 25% of what's left to her brother, so she has (0.75*0.72) $\boxed{\textbf{(E)}\ 54}$. of what she had in the beginning left.~heeeeeeeheeeeee ar

See Also

2019 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 7
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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