Difference between revisions of "2019 Mock AMC 10B Problems/Problem 2"
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Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have <math>{6 \choose 3}=15</math> | Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have <math>{6 \choose 3}=15</math> | ||
− | <cmath>\boxed{\bold{C}}</ | + | <cmath></cmath><math>\boxed{\bold{C}}</math> |
− | < | + | <math>\bold{15}</math> |
Revision as of 11:43, 20 January 2020
Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have