Difference between revisions of "2019 Mock AMC 10B Problems/Problem 2"
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| − | + | Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have <math>{6 \choose 3}=15</math> | |
Revision as of 00:29, 23 September 2019
Simply choosing 3 of the boy scouts predetermines the other 3 boy scouts so we have 
