2020 AIME I Problems/Problem 7

Revision as of 17:15, 12 March 2020 by Awang11 (talk | contribs) (Solution)

Note: Please do not post problems here until after the AIME.

Problem

Solution

We will be selecting girls, but not selecting boys. We claim that the amount of girls selected and the amount of guys not selected adds to $12$. This is easy to see: if $k$ women were chosen, then $k + (11 - k + 1) = 12$. Therefore, we simply take $\binom{23}{12} \implies \boxed{081}$. ~awang11's sol

See Also

2020 AIME I (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All AIME Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png