Difference between revisions of "2020 AMC 10B Problems/Problem 1"

(Problem 1)
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We know that when we subtract negative numbers, <math>a-(-b)=a+b</math>.
 
We know that when we subtract negative numbers, <math>a-(-b)=a+b</math>.
  
The equation becomes <math>1+2-3+4-5+6 = \boxed{\textbf{(D)}\ 5}</math>
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The equation becomes <math>1+2-3+4-5+6 = \boxed{\textbf{(D)}\ 5}</math> ~quacker88
  
== Solution ==
 
Solution
 
 
==Video Solution==
 
==Video Solution==
YouTube Link
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https://youtu.be/Gkm5rU5MlOU
== See Also ==
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 +
~IceMatrix
 +
 
 +
 
 +
https://youtu.be/-wciFhP5h3I
 +
 
 +
~savannahsolver
 +
 
 +
==See Also==
  
 
{{AMC10 box|year=2020|ab=B|before=First Problem|num-a=2}}
 
{{AMC10 box|year=2020|ab=B|before=First Problem|num-a=2}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 16:52, 16 June 2020

Problem

What is the value of \[1-(-2)-3-(-4)-5-(-6)?\]

$\textbf{(A)}\ -20 \qquad\textbf{(B)}\ -3 \qquad\textbf{(C)}\  3 \qquad\textbf{(D)}\ 5 \qquad\textbf{(E)}\ 21$

Solution

We know that when we subtract negative numbers, $a-(-b)=a+b$.

The equation becomes $1+2-3+4-5+6 = \boxed{\textbf{(D)}\ 5}$ ~quacker88

Video Solution

https://youtu.be/Gkm5rU5MlOU

~IceMatrix


https://youtu.be/-wciFhP5h3I

~savannahsolver

See Also

2020 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
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All AMC 10 Problems and Solutions

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