Difference between revisions of "2020 AMC 10B Problems/Problem 7"

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Even numbers are divisible by 2, and thus the numbers we are looking for are divisible by 3 X 2, or 6. The square numbers will be 36 X other square numbers. 36X1, 36X4, 36X9, 36X16, 36X25, 36X36, 36X49 are all less than 2020. There are 7 of these square numbers divisible by 6, so the answer is 7
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==Problem==
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How many positive even multiples of <math>3</math> less than <math>2020</math> are perfect squares?
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<math>\textbf{(A)}\ 7 \qquad\textbf{(B)}\ 8 \qquad\textbf{(C)}\  9 \qquad\textbf{(D)}\ 10 \qquad\textbf{(E)}\ 12</math>
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==Solution==
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Any even multiple of <math>3</math> is a multiple of <math>6</math>, so we need to find multiples of <math>6</math> that are perfect squares and less than <math>2020</math>. Any solution that we want will be in the form <math>(6n)^2</math>, where <math>n</math> is a positive integer. The smallest possible value is at <math>n=1</math>, and the largest is at <math>n=7</math> (where the expression equals <math>1764</math>). Therefore, there are a total of <math>\boxed{\textbf{(A)}\ 7}</math> possible numbers.-PCChess
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==Video Solution==
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https://youtu.be/OHR_6U686Qg
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~IceMatrix
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https://youtu.be/5cDMRWNrH-U
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~savannahsolver
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==See Also==
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{{AMC10 box|year=2020|ab=B|num-b=6|num-a=8}}
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{{MAA Notice}}

Revision as of 14:51, 30 June 2020

Problem

How many positive even multiples of $3$ less than $2020$ are perfect squares?

$\textbf{(A)}\ 7 \qquad\textbf{(B)}\ 8 \qquad\textbf{(C)}\  9 \qquad\textbf{(D)}\ 10 \qquad\textbf{(E)}\ 12$

Solution

Any even multiple of $3$ is a multiple of $6$, so we need to find multiples of $6$ that are perfect squares and less than $2020$. Any solution that we want will be in the form $(6n)^2$, where $n$ is a positive integer. The smallest possible value is at $n=1$, and the largest is at $n=7$ (where the expression equals $1764$). Therefore, there are a total of $\boxed{\textbf{(A)}\ 7}$ possible numbers.-PCChess

Video Solution

https://youtu.be/OHR_6U686Qg

~IceMatrix

https://youtu.be/5cDMRWNrH-U

~savannahsolver

See Also

2020 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

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