Difference between revisions of "2020 AMC 8 Problems/Problem 1"
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==Solution 1== | ==Solution 1== | ||
− | Luka will need <math>3\cdot 2=6</math> cups of sugar, and thus <math>6\cdot 4=24</math> cups of water. The answer is <math>\boxed{\textbf{(E) } | + | Luka will need <math>3\cdot 2=6</math> cups of sugar, and thus <math>6\cdot 4=24</math> cups of water. The answer is <math>\boxed{\textbf{(E) } 24}</math>. |
==Solution 2== | ==Solution 2== |
Revision as of 12:51, 23 November 2020
Problem
Luka is making lemonade to sell at a school fundraiser. His recipe requires times as much water as sugar and twice as much sugar as lemon juice. He uses cups of lemon juice. How many cups of water does he need?
Solution 1
Luka will need cups of sugar, and thus cups of water. The answer is .
Solution 2
We have that , so Luka needs cups.
Video Solution
See also
2020 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by First problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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