# 2020 AMC 8 Problems/Problem 17

(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

How many positive integer factors of $2020$ have more than $3$ factors?

$\textbf{(A) }6 \qquad \textbf{(B) }7 \qquad \textbf{(C) }8 \qquad \textbf{(D) }9 \qquad \textbf{(E) }10$

## Solution

We list out the factors of $2020$: $$1, 2, 4, 5, 10, 20, 101, 202, 404, 505, 1010, 2020.$$ Of these, only $1, 2, 4, 5, 101$ ($5$ of them) do not have more than $3$ factors. Therefore the answer is $\tau{2020}-5=\boxed{\textbf{(B) }7}$.