Difference between revisions of "2020 AMC 8 Problems/Problem 2"
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| − | == | + | ==Problem== |
| − | 4 | + | 4 friends do yardwork for their neighbors over the weekend, earning <math>\$15, \$20, \$25,</math> and <math>\$40,</math> respectively. The Friends decide to split their earnings equally among themselves. In total how much will friend 1 who earned <math>\$40</math> give to the friends? |
if you were a joshy dis would be easy | if you were a joshy dis would be easy | ||
<math>\textbf{(A) }\$5 \qquad \textbf{(B) }\$10 \qquad \textbf{(C) }\$15 \qquad \textbf{(D) }\$20 \qquad \textbf{(E) }\$25</math>s | <math>\textbf{(A) }\$5 \qquad \textbf{(B) }\$10 \qquad \textbf{(C) }\$15 \qquad \textbf{(D) }\$20 \qquad \textbf{(E) }\$25</math>s | ||
Revision as of 12:42, 4 December 2021
Contents
Problem
4 friends do yardwork for their neighbors over the weekend, earning 
and 
respectively. The Friends decide to split their earnings equally among themselves. In total how much will friend 1 who earned 
give to the friends?
if you were a joshy dis would be easy
s
Solution
The friends earn 
in total. Since they decided to split their earnings equally, it follows that each person will get 
. Since the friend who earned will need to leave with 
, he will have to give 
to the others.
Video Solution by WhyMath
~savannahsolver
Video Solution by North America Math Contest Go Go Go
https://www.youtube.com/watch?v=ZwfPEYd55NQ
~North America Math Contest Go Go Go
Video Solution
Video Solution by Interstigation
https://youtu.be/YnwkBZTv5Fw?t=62
~Interstigation
See also
| 2020 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 1 |
Followed by Problem 3 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
