Difference between revisions of "2020 AMC 8 Problems/Problem 3"

(See also)
Line 6: Line 6:
 
==Solution==
 
==Solution==
 
The answer is the product of the area of the field, the amount of strawberries per plant, and the amount of plants in one square feet. The answer is <math>6 \times 8 \times 10 \times 4 = 1920</math> or <math>\boxed{\textbf{D }1920}</math>.
 
The answer is the product of the area of the field, the amount of strawberries per plant, and the amount of plants in one square feet. The answer is <math>6 \times 8 \times 10 \times 4 = 1920</math> or <math>\boxed{\textbf{D }1920}</math>.
 +
 +
==Solution 2==
 +
The area of the garden is <math>6 ft \times 8 ft = 48</math> square feet. Since Carrie plants <math>4</math> strawberry plants per square foot, it follows that she plants a total of <math>48 \times 4=192</math> strawberry plants. Since each strawberry plant produces on average 10 strawberries, it follows that she can expect to harvest <math>192 \times 10=1920</math> strawberries <math>\implies\boxed{\textbf{(D) }1920}</math>.<br>
 +
~jmansuri
  
 
==See also==  
 
==See also==  
 
{{AMC8 box|year=2020|num-b=2|num-a=4}}
 
{{AMC8 box|year=2020|num-b=2|num-a=4}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 04:30, 18 November 2020

Problem 3

Carrie has a rectangular garden that measures $6$ feet by $8$ feet. She plants the entire garden with strawberry plants. Carrie is able to plant $4$ strawberry plants per square foot, and she harvests an average of $10$ strawberries per plant. How many strawberries can she expect to harvest?

$\textbf{(A) }560 \qquad \textbf{(B) }960 \qquad \textbf{(C) }1120 \qquad \textbf{(D) }1920 \qquad \textbf{(E) }3840$

Solution

The answer is the product of the area of the field, the amount of strawberries per plant, and the amount of plants in one square feet. The answer is $6 \times 8 \times 10 \times 4 = 1920$ or $\boxed{\textbf{D }1920}$.

Solution 2

The area of the garden is $6 ft \times 8 ft = 48$ square feet. Since Carrie plants $4$ strawberry plants per square foot, it follows that she plants a total of $48 \times 4=192$ strawberry plants. Since each strawberry plant produces on average 10 strawberries, it follows that she can expect to harvest $192 \times 10=1920$ strawberries $\implies\boxed{\textbf{(D) }1920}$.
~jmansuri

See also

2020 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png