# Difference between revisions of "2020 AMC 8 Problems/Problem 3"

## Problem 3

Carrie has a rectangular garden that measures $6$ feet by $8$ feet. She plants the entire garden with strawberry plants. Carrie is able to plant $4$ strawberry plants per square foot, and she harvests an average of $10$ strawberries per plant. How many strawberries can she expect to harvest?

$\textbf{(A) }560 \qquad \textbf{(B) }960 \qquad \textbf{(C) }1120 \qquad \textbf{(D) }1920 \qquad \textbf{(E) }3840$

## Solution

The answer is the product of the area of the field, the amount of strawberries per plant, and the amount of plants in one square feet. The answer is $6 \times 8 \times 10 \times 4 = 1920$ or $\boxed{\textbf{(D) }1920}$.

## Solution 2

The area of the garden is $6$ ft $\times$ $8$ ft $= 48$ square feet. Since Carrie plants $4$ strawberry plants per square foot, it follows that she plants a total of $48 \times 4=192$ strawberry plants. Since each strawberry plant produces on average 10 strawberries, it follows that she can expect to harvest $192 \times 10=1920$ strawberries $\implies\boxed{\textbf{(D) }1920}$.
~junaidmansuri

## Solution 3

Note that $6\cdot 8 = 48$, so Carrie has $4\cdot 48 = 192$ strawberry plants. Each plant produces $10$ strawberries, so the final answer is $192\cdot 10 = \textbf{(D)}\ 1920$.'

## Solution 4

The answer is $6 \times 8 \times 10 \times 4 = 1920$ or $\boxed{\textbf{(D) }1920}$.


-oceanxia

-franzliszt

~savannahsolver

## See also

 2020 AMC 8 (Problems • Answer Key • Resources) Preceded byProblem 2 Followed byProblem 4 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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