Difference between revisions of "2020 AMC 8 Problems/em 1"
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+ | ==Problem== | ||
+ | Four friends do yardwork for their neighbors over the weekend, earning <math>\$15, \$20, \$25,</math> and <math>\$40,</math> respectively. They decide to split their earnings equally among themselves. In total how much will the friend who earned <math>\$40</math> give to the others? | ||
+ | |||
+ | ==Solution== | ||
Since the amount of sugar is twice the amount of lemon juice, Luka uses <math>3\cdot2=6</math> cups of sugar. | Since the amount of sugar is twice the amount of lemon juice, Luka uses <math>3\cdot2=6</math> cups of sugar. | ||
Since the amount of water is <math>4</math> times the amount of sugar, he uses <math>6\cdot4=\boxed{\text{(E) }24}</math> cups of water. | Since the amount of water is <math>4</math> times the amount of sugar, he uses <math>6\cdot4=\boxed{\text{(E) }24}</math> cups of water. | ||
+ | |||
+ | ==See also== | ||
+ | {{AMC8 box|year=2020|before = First Problem|num-a=2}} | ||
+ | {{MAA Notice}} |
Latest revision as of 10:47, 12 February 2021
Problem
Four friends do yardwork for their neighbors over the weekend, earning and respectively. They decide to split their earnings equally among themselves. In total how much will the friend who earned give to the others?
Solution
Since the amount of sugar is twice the amount of lemon juice, Luka uses cups of sugar.
Since the amount of water is times the amount of sugar, he uses cups of water.
See also
2020 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by First Problem |
Followed by Problem 2 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.