2020 CIME I Problems/Problem 7
For every positive integer , define Suppose that the sum can be expressed as for relatively prime integers and . Find the remainder when is divided by .
Let . We claim that We show this using induction. Suppose this is true for some . Then, it must be true for . The base case when is trivial. Then, we have that Hence, this completes the induction therefore proving the claim. So, the numerator is . We proceed using Euler's Theorem combined with Chinese Remainder Theorem. It is obvious that so . Also, instead of considering modulo , we consider it modulo . Then, we get by Euler's Totient Theorem as . This implies that , so . Solving the system of congruences, we get . ~rocketsri (based off of official solution)
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