# Difference between revisions of "2021 AMC 10A Problems/Problem 11"

## Problem

For which of the following integers $b$ is the base- $b$ number $2021_b - 221_b$ not divisible by $3$? $\textbf{(A)} ~3 \qquad\textbf{(B)} ~4\qquad\textbf{(C)} ~6\qquad\textbf{(D)} ~7\qquad\textbf{(E)} ~8$

## Solution 1

We have $$2021_b - 221_b = 2000_b - 200_b = 2b^3 - 2b^2 = 2b^2(b-1).$$ This expression is divisible by $3$ unless $b\equiv2\pmod{3}.$ The only choice congruent to $2$ modulo $3$ is $\boxed{\textbf{(E)} ~8}.$

~MRENTHUSIASM

## Solution 2

Vertically subtracting $$2021_b - 221_b$$ we see that the ones place becomes 0, the b^1 place becomes 0 as well. Now, at the $$b^2$$ place, we must perform a carry, but instead of incrementing the place's value by 10 like we normally would in base 10, we do so by $b$, and make the $$b^3$$ place in $$2021_b$$ equal to 1. Thus, we have our final number as  (Error compiling LaTeX. ! Missing \$ inserted.)1100_b.

## Video Solution (Simple and Quick)

~ Education, the Study of Everything

## Video Solution

~North America Math Contest Go Go Go

~savannahsolver

~IceMatrix

## See Also

 2021 AMC 10A (Problems • Answer Key • Resources) Preceded byProblem 10 Followed byProblem 12 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 All AMC 10 Problems and Solutions

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