Difference between revisions of "2021 AMC 10B Problems/Problem 2"

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(Solution)
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Summed up you get <math>\boxed{\textbf{(D)} ~4\sqrt{3}}</math> ~bjc and abhinavg0627
 
Summed up you get <math>\boxed{\textbf{(D)} ~4\sqrt{3}}</math> ~bjc and abhinavg0627
  
\phantom{no problem bjc}
+
<math>\phantom{no problem bjc}</math>
  
 
==Video Solution==
 
==Video Solution==
 
https://youtu.be/HHVdPTLQsLc
 
https://youtu.be/HHVdPTLQsLc
 
~Math Python
 
~Math Python

Revision as of 19:37, 11 February 2021

Problem

What is the value of \[\sqrt{(3-2\sqrt{3})^2}+\sqrt{(3+2\sqrt{3})^2}?\]

$\textbf{(A)} ~0 \qquad\textbf{(B)} ~4\sqrt{3}-6 \qquad\textbf{(C)} ~6 \qquad\textbf{(D)} ~4\sqrt{3} \qquad\textbf{(E)} ~4\sqrt{3}+6$

Solution

Note that the square root of a squared number is the absolute value of the number because the square root function always gives a positive number. We know that $3-2\sqrt{3}$ is actually negative, thus the absolute value is not $3-2\sqrt{3}$ but $2\sqrt{3} - 3$. So the first term equals $2\sqrt{3}-3$ and the second term is $3+2\sqrt3$ Summed up you get $\boxed{\textbf{(D)} ~4\sqrt{3}}$ ~bjc and abhinavg0627

$\phantom{no problem bjc}$

Video Solution

https://youtu.be/HHVdPTLQsLc ~Math Python