# Difference between revisions of "2021 April MIMC 10"

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+ | <math>\textit{This is a mock contest of the actual AMC competition. Feel free to add more solutions beneath the official solution.}</math> | ||

==Problem 1== | ==Problem 1== | ||

What is the sum of <math>2^{3}-(-3^{4})-3^{4}+1</math>? | What is the sum of <math>2^{3}-(-3^{4})-3^{4}+1</math>? | ||

Line 93: | Line 94: | ||

==Problem 14== | ==Problem 14== | ||

James randomly choose an ordered pair <math>(x,y)</math> which both <math>x</math> and <math>y</math> are elements in the set <math>\{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15\}</math>, <math>x</math> and <math>y</math> are not necessarily distinct, and all of the equations: | James randomly choose an ordered pair <math>(x,y)</math> which both <math>x</math> and <math>y</math> are elements in the set <math>\{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15\}</math>, <math>x</math> and <math>y</math> are not necessarily distinct, and all of the equations: | ||

− | < | + | <cmath>x+y</cmath> |

+ | <cmath>x^2+y^2</cmath> | ||

+ | <cmath>x^4+y^4</cmath> | ||

are divisible by <math>5</math>. Find the probability that James can do so. | are divisible by <math>5</math>. Find the probability that James can do so. | ||

+ | |||

+ | <math>\textbf{(A)} ~\frac{1}{25} \qquad\textbf{(B)} ~\frac{2}{45} \qquad\textbf{(C)} ~\frac{11}{225} \qquad\textbf{(D)} ~\frac{4}{75} \qquad\textbf{(E)} ~\frac{13}{225}</math> | ||

+ | |||

+ | [[2021 April MIMC 10 Problems/Problem 14 |Solution]] | ||

+ | |||

+ | ==Problem 15== | ||

+ | Paul wrote all positive integers that's less than <math>2021</math> and wrote their base <math>4</math> representation. He randomly choose a number out the list. Paul insist that he want to choose a number that had only <math>2</math> and <math>3</math> as its digits, otherwise he will be depressed and relinquishes to do homework. How many numbers can he choose so that he can finish his homework? | ||

+ | |||

+ | <math>\textbf{(A)} ~30 \qquad\textbf{(B)} ~62 \qquad\textbf{(C)} ~64 \qquad\textbf{(D)} ~84 \qquad\textbf{(E)} ~126</math> | ||

+ | |||

+ | [[2021 April MIMC 10 Problems/Problem 15 |Solution]] | ||

+ | |||

+ | ==Problem 16== | ||

+ | Find the number of permutations of <math>AAABBC</math> such that at exactly two <math>A</math>s are adjacent, and the <math>B</math>s are not adjacent. | ||

+ | |||

+ | <math>\textbf{(A)} ~21 \qquad\textbf{(B)} ~22 \qquad\textbf{(C)} ~23 \qquad\textbf{(D)} ~24 \qquad\textbf{(E)} ~25</math> | ||

+ | |||

+ | [[2021 April MIMC 10 Problems/Problem 16 |Solution]] | ||

+ | |||

+ | ==Problem 17== | ||

+ | The following expression <cmath>\sum_{k=1}^{60} {60 \choose k}+\sum_{k=1}^{59} {59 \choose k}+\sum_{k=1}^{58} {58 \choose k}+\sum_{k=1}^{57} {57 \choose k}+\sum_{k=1}^{56} {56 \choose k}+\sum_{k=1}^{55} {55 \choose k}+\sum_{k=1}^{54} {54 \choose k}+...+\sum_{k=1}^{3} {3 \choose k}-2^{10}</cmath> can be expressed as <math>x^{y}-z</math> which both <math>x</math> and <math>y</math> are relatively prime positive integers. Find <math>2^{x}(xy+2x+z)</math>. | ||

+ | |||

+ | <math>\textbf{(A)} ~4632 \qquad\textbf{(B)} ~4844 \qquad\textbf{(C)} ~4860\qquad\textbf{(D)} ~4864 \qquad\textbf{(E)} ~8960</math> | ||

+ | |||

+ | [[2021 April MIMC 10 Problems/Problem 17 |Solution]] | ||

+ | |||

+ | ==Problem 18== | ||

+ | What can be a description of the set of solutions for this: <math>x^{2}+y^{2}=|2x+|2y||</math>? | ||

+ | |||

+ | <math>\textbf{(A)}</math> Two overlapping circles with each area <math>2\pi</math>. | ||

+ | |||

+ | <math>\textbf{(B)}</math> Four not overlapping circles with each area <math>4\pi</math>. | ||

+ | |||

+ | <math>\textbf{(C)}</math> There are two overlapping circles on the right of the <math>y</math>-axis with each area <math>2\pi</math> and the intersection area of two overlapping circles on the left of the <math>y</math>-axis with each area <math>2\pi</math>. | ||

+ | |||

+ | <math>\textbf{(D)}</math> Four overlapping circles with each area <math>4\pi</math>. | ||

+ | |||

+ | <math>\textbf{(E)}</math> There are two overlapping circles on the right of the <math>y</math>-axis with each area <math>4\pi</math> and the intersection area of two overlapping circles on the left of the <math>y</math>-axis with each area <math>4\pi</math>. | ||

+ | |||

+ | [[2021 April MIMC 10 Problems/Problem 18 |Solution]] | ||

+ | |||

+ | ==Problem 19== | ||

+ | <math>(0.51515151...)_n</math> can be expressed as <math>(\frac{6}{n})</math> in base <math>10</math> which <math>n</math> is a positive integer. Find the sum of the digits of <math>n^{3}</math>. | ||

+ | |||

+ | <math>\textbf{(A)} ~6 \qquad\textbf{(B)} ~7 \qquad\textbf{(C)} ~8 \qquad\textbf{(D)} ~9 \qquad \textbf{(E)} ~\textrm{Does Not Exist}</math> | ||

+ | |||

+ | [[2021 April MIMC 10 Problems/Problem 19 |Solution]] | ||

+ | |||

+ | ==Problem 20== | ||

+ | Given that <math>y=24\cdot 34\cdot 67\cdot 89</math>. Given that the product of the even divisors is <math>a</math>, and the product of the odd divisors is <math>b</math>. Find <math>a \colon b^4</math>. | ||

+ | |||

+ | <math>\textbf{(A)} ~512:1 \qquad\textbf{(B)} ~1024:1 \qquad\textbf{(C)} ~2^{64}:1 \qquad\textbf{(D)} ~2^{80}:1 \qquad\textbf{(E)} ~2^{160}:1 \qquad</math> | ||

+ | |||

+ | [[2021 April MIMC 10 Problems/Problem 20 |Solution]] | ||

+ | |||

+ | ==Problem 21== | ||

+ | How many solutions are there for the equation <math>\left \lfloor{x}\right \rfloor^{2}-\left \lceil{x}\right \rceil=0</math>. (Recall that <math>\left \lfloor{x}\right \rfloor</math> is the largest integer less than <math>x</math>, and <math>\left \lceil{x}\right \rceil</math> is the smallest integer larger than <math>x</math>.) | ||

+ | |||

+ | <math>\textbf{(A)} ~0 \qquad\textbf{(B)} ~1 \qquad\textbf{(C)} ~2 \qquad\textbf{(D)} ~3 \qquad\textbf{(E)} ~4 \qquad</math> | ||

+ | |||

+ | [[2021 April MIMC 10 Problems/Problem 21 |Solution]] | ||

+ | |||

+ | ==Problem 22== | ||

+ | In the diagram, <math>ABCD</math> is a square with area <math>6+4\sqrt{2}</math>. <math>AC</math> is a diagonal of square <math>ABCD</math>. Square <math>IGED</math> has area <math>11-6\sqrt{2}</math>. Given that point <math>J</math> bisects line segment <math>HE</math>, and <math>AE</math> is a line segment. Extend <math>EG</math> to meet diagonal <math>AC</math> and mark the intersection point <math>H</math>. In addition, <math>K</math> is drawn so that <math>JK//EC</math>. <math>FH^2</math> can be represented as <math>\frac{a+b\sqrt{c}}{{d}}</math> where <math>a,b,c,d</math> are not necessarily distinct integers. Given that <math>gcd(a,b,d)=1</math>, and <math>c</math> does not have a perfect square factor. Find <math>a+b+c+d</math>. | ||

+ | |||

+ | [[File:24.png]] | ||

+ | |||

+ | <math>\textbf{(A)} ~5 \qquad\textbf{(B)} ~15 \qquad\textbf{(C)} ~61 \qquad\textbf{(D)} ~349 \qquad\textbf{(E)} ~2009 \qquad</math> | ||

+ | |||

+ | [[2021 April MIMC 10 Problems/Problem 22 |Solution]] | ||

+ | |||

+ | ==Problem 23== | ||

+ | On a coordinate plane, point <math>O</math> denotes the origin which is the center of the diamond shape in the middle of the figure. Point <math>A</math> has coordinate <math>(-12,12)</math>, and point <math>C</math>, <math>E</math>, and <math>G</math> are formed through <math>90^{\circ}</math>, <math>180^{\circ}</math>, and <math>270^{\circ}</math> rotation about the origin <math>O</math>, respectively. Quarter circle <math>BOH</math> (formed by the arc <math>BH</math> and line segments <math>BO</math> and <math>GH</math>) has area <math>25\pi</math>. Furthermore, another quarter circle <math>DOF</math> formed by arc <math>DF</math> and line segments <math>OF</math>, <math>OD</math> is formed through a reflection of sector <math>BOH</math> across the line <math>y=x</math>. The small diamond centered at <math>O</math> is a square, and the area of the little square is <math>2</math>. Let <math>x</math> denote the area of the shaded region, and <math>y</math> denote the sum of the area of the regions <math>ABH</math> (formed by side <math>AB</math>, arc <math>BH</math>, and side <math>HA</math>), <math>DFE</math> (formed by side <math>ED</math>, arc <math>DF</math>, and side <math>FE</math>) and sectors <math>FGH</math> and <math>BCD</math>. Find <math>\frac{x}{y}</math> in the simplest radical form. | ||

+ | |||

+ | [[File:19 (1).png|500px]] | ||

+ | |||

+ | <math>\textbf{(A)} ~\frac{50\pi+1}{280} \qquad\textbf{(B)} ~\frac{50\pi\sqrt{2}+\sqrt{2}}{560} \qquad\textbf{(C)} ~\frac{50\pi+1}{140+100\pi} \qquad\textbf{(D)} ~\frac{50\pi+1}{280+100\pi} \qquad\textbf{(E)} ~\frac{50\pi^2+700\pi\sqrt{2}+3001\pi-70\sqrt{2}+60}{2\pi^2+240\pi+6920}\qquad</math> | ||

+ | |||

+ | [[2021 April MIMC 10 Problems/Problem 23 |Solution]] | ||

+ | |||

+ | ==Problem 24== | ||

+ | One semicircle is constructed with diameter <math>AH=4</math> and let the midpoint of <math>AH</math> be <math>M</math>. Construct a point <math>O</math> on the side of segment <math>AH</math> (closer to segment <math>AH</math> than arc <math>AH</math>) such that the distance from <math>A</math> to <math>O</math> is <math>2\sqrt{5}</math>, and that <math>OM</math> is perpendicular to the diameter <math>AH</math>. Three more such congruent semicircles are formed through multiple <math>90^{\circ}</math>rotations around the point <math>O</math>. Name the <math>6</math> endpoints of the diameters <math>B</math>, <math>C</math>, <math>D</math>, <math>E</math>, <math>F</math>, <math>G</math> in a circular direction from <math>A</math> to <math>H</math>. Another four congruent semicircles are constructed with diameters <math>AB, CD, EF, GH</math>, and that the distance from the diameters to the point <math>O</math> are less than the distance from the arcs to the point <math>O</math>. Connect <math>AC</math>, <math>CD</math>, <math>DO</math>, <math>OG</math>, and <math>GA</math>. Find the ratio of the area of the pentagon <math>ACDOG</math> to the total area of the shape formed by arcs <math>AB</math>, <math>BC</math>, <math>CD</math>, <math>DE</math>, <math>EF</math>, <math>FG</math>, <math>GH</math>, <math>HA</math>. | ||

+ | |||

+ | <math>\textbf{(A)} ~\frac{14+10\pi}{17} \qquad\textbf{(B)} ~\frac{13+\sqrt{2}}{28} \qquad\textbf{(C)} ~\frac{4+\sqrt{2}}{7+3\pi} \qquad\textbf{(D)} ~\frac{13}{28+6\pi} \qquad\textbf{(E)} ~\frac{13}{30\pi}\qquad</math> | ||

+ | |||

+ | [[2021 April MIMC 10 Problems/Problem 24 |Solution]] | ||

+ | |||

+ | ==Problem 25== | ||

+ | Suppose that a researcher hosts an experiment. He tosses an equilateral triangle with area <math>\sqrt{3}</math> <math>cm^2</math> onto a plane that has a strip every <math>1</math> <math>cm</math> horizontally. Find the expected number of intersections of the strips and the sides of the equilateral triangle. | ||

+ | |||

+ | [[File:25.png|500px]] | ||

+ | |||

+ | <math>\textbf{(A)} ~4 \qquad\textbf{(B)} ~\frac{12}{\pi} \qquad\textbf{(C)} ~\frac{2+3\sqrt{3}}{2} \qquad\textbf{(D)} ~\frac{4+\sqrt{3}}{2} \qquad\textbf{(E)} ~\frac{12+4\sqrt{2}-2\sqrt{3}}{4}\qquad</math> | ||

+ | |||

+ | [[2021 April MIMC 10 Problems/Problem 25 |Solution]] | ||

+ | |||

+ | ==Additional Information== | ||

+ | 1. The Committee on the Michael595 & Interstigation Math Contest (MIMC) reserves the right to re-examine students before deciding whether to grant official status to their scores. The MIMC also reserves the right to disqualify score from a test taker if it is determined that the required security procedures were not followed. | ||

+ | |||

+ | 2. The publication, reproduction or communication of the problems or solutions of the MIMC 10 will result in disqualification. Dissemination via copier, telephone, e-mail, World Wide Web or media of any type during this period is a violation of the competition rules except the private discussion form. | ||

+ | |||

+ | Sincerely, the MIMC mock contest cannot come true without the contributions from the following testsolvers, problem writers and advisors: | ||

+ | <cmath>\textrm{Interstigation (Problem Writer)}</cmath> | ||

+ | <cmath>\textrm{Michael595 (Problem Writer)}</cmath> | ||

+ | <cmath>\textrm{Fidgetboss\_4000 (Testsolver)}</cmath> | ||

+ | <cmath>\textrm{Skyscraper (Suggester)}</cmath> |

## Latest revision as of 13:52, 26 April 2021

## Contents

- 1 Problem 1
- 2 Problem 2
- 3 Problem 3
- 4 Problem 4
- 5 Problem 5
- 6 Problem 6
- 7 Problem 7
- 8 Problem 8
- 9 Problem 9
- 10 Problem 10
- 11 Problem 11
- 12 Problem 12
- 13 Problem 13
- 14 Problem 14
- 15 Problem 15
- 16 Problem 16
- 17 Problem 17
- 18 Problem 18
- 19 Problem 19
- 20 Problem 20
- 21 Problem 21
- 22 Problem 22
- 23 Problem 23
- 24 Problem 24
- 25 Problem 25
- 26 Additional Information

## Problem 1

What is the sum of ?

## Problem 2

Okestima is reading a page book. He reads a page every minutes, and he pauses minutes when he reaches the end of page 90 to take a break. He does not read at all during the break. After, he comes back with food and this slows down his reading speed. He reads one page in minutes. If he starts to read at , when does he finish the book?

## Problem 3

Find the number of real solutions that satisfy the equation .

## Problem 4

Stiskwey wrote all the possible permutations of the letters ( is different from ). How many such permutations are there?

## Problem 5

5. Given , Find .

## Problem 6

A worker cuts a piece of wire into two pieces. The two pieces, and , enclose an equilateral triangle and a square with equal area, respectively. The ratio of the length of to the length of can be expressed as in the simplest form. Find .

## Problem 7

Find the least integer such that where denotes in base-.

## Problem 8

In the morning, Mr.Gavin always uses his alarm to wake him up. The alarm is special. It always rings in a cycle of ten rings. The first ring lasts second, and each ring after lasts twice the time than the previous ring. Given that Mr.Gavin has an equal probability of waking up at any time, what is the probability that Mr.Gavin wakes up and end the alarm during the tenth ring?

## Problem 9

Find the largest number in the choices that divides .

## Problem 10

If and , find .

## Problem 11

How many factors of is a perfect cube or a perfect square?

## Problem 12

Given that , what is ?

## Problem 13

Given that Giant want to put green identical balls into different boxes such that each box contains at least two balls, and that no box can contain or more balls. Find the number of ways that Giant can accomplish this.

## Problem 14

James randomly choose an ordered pair which both and are elements in the set , and are not necessarily distinct, and all of the equations: are divisible by . Find the probability that James can do so.

## Problem 15

Paul wrote all positive integers that's less than and wrote their base representation. He randomly choose a number out the list. Paul insist that he want to choose a number that had only and as its digits, otherwise he will be depressed and relinquishes to do homework. How many numbers can he choose so that he can finish his homework?

## Problem 16

Find the number of permutations of such that at exactly two s are adjacent, and the s are not adjacent.

## Problem 17

The following expression can be expressed as which both and are relatively prime positive integers. Find .

## Problem 18

What can be a description of the set of solutions for this: ?

Two overlapping circles with each area .

Four not overlapping circles with each area .

There are two overlapping circles on the right of the -axis with each area and the intersection area of two overlapping circles on the left of the -axis with each area .

Four overlapping circles with each area .

There are two overlapping circles on the right of the -axis with each area and the intersection area of two overlapping circles on the left of the -axis with each area .

## Problem 19

can be expressed as in base which is a positive integer. Find the sum of the digits of .

## Problem 20

Given that . Given that the product of the even divisors is , and the product of the odd divisors is . Find .

## Problem 21

How many solutions are there for the equation . (Recall that is the largest integer less than , and is the smallest integer larger than .)

## Problem 22

In the diagram, is a square with area . is a diagonal of square . Square has area . Given that point bisects line segment , and is a line segment. Extend to meet diagonal and mark the intersection point . In addition, is drawn so that . can be represented as where are not necessarily distinct integers. Given that , and does not have a perfect square factor. Find .

## Problem 23

On a coordinate plane, point denotes the origin which is the center of the diamond shape in the middle of the figure. Point has coordinate , and point , , and are formed through , , and rotation about the origin , respectively. Quarter circle (formed by the arc and line segments and ) has area . Furthermore, another quarter circle formed by arc and line segments , is formed through a reflection of sector across the line . The small diamond centered at is a square, and the area of the little square is . Let denote the area of the shaded region, and denote the sum of the area of the regions (formed by side , arc , and side ), (formed by side , arc , and side ) and sectors and . Find in the simplest radical form.

## Problem 24

One semicircle is constructed with diameter and let the midpoint of be . Construct a point on the side of segment (closer to segment than arc ) such that the distance from to is , and that is perpendicular to the diameter . Three more such congruent semicircles are formed through multiple rotations around the point . Name the endpoints of the diameters , , , , , in a circular direction from to . Another four congruent semicircles are constructed with diameters , and that the distance from the diameters to the point are less than the distance from the arcs to the point . Connect , , , , and . Find the ratio of the area of the pentagon to the total area of the shape formed by arcs , , , , , , , .

## Problem 25

Suppose that a researcher hosts an experiment. He tosses an equilateral triangle with area onto a plane that has a strip every horizontally. Find the expected number of intersections of the strips and the sides of the equilateral triangle.

## Additional Information

1. The Committee on the Michael595 & Interstigation Math Contest (MIMC) reserves the right to re-examine students before deciding whether to grant official status to their scores. The MIMC also reserves the right to disqualify score from a test taker if it is determined that the required security procedures were not followed.

2. The publication, reproduction or communication of the problems or solutions of the MIMC 10 will result in disqualification. Dissemination via copier, telephone, e-mail, World Wide Web or media of any type during this period is a violation of the competition rules except the private discussion form.

Sincerely, the MIMC mock contest cannot come true without the contributions from the following testsolvers, problem writers and advisors: