Difference between revisions of "2021 April MIMC 10 Problems/Problem 20"
Cellsecret (talk | contribs) (Created page with "Given that <math>y=24\cdot 34\cdot 67\cdot 89</math>. Given that the product of the even divisors is <math>a</math>, and the product of the odd divisors is <math>b</math>. Fin...") |
Cellsecret (talk | contribs) |
||
| Line 1: | Line 1: | ||
Given that <math>y=24\cdot 34\cdot 67\cdot 89</math>. Given that the product of the even divisors is <math>a</math>, and the product of the odd divisors is <math>b</math>. Find <math>a \colon b^4</math>. | Given that <math>y=24\cdot 34\cdot 67\cdot 89</math>. Given that the product of the even divisors is <math>a</math>, and the product of the odd divisors is <math>b</math>. Find <math>a \colon b^4</math>. | ||
| − | <math>\textbf{(A)} ~512:1 \qquad\textbf{(B)} ~1024:1 \qquad\textbf{(C)} ~2^{64}:1 \qquad\textbf{(D)} ~2^{80}:1 \qquad\textbf{(E)} 2^{160}:1 \qquad</math> | + | <math>\textbf{(A)} ~512:1 \qquad\textbf{(B)} ~1024:1 \qquad\textbf{(C)} ~2^{64}:1 \qquad\textbf{(D)} ~2^{80}:1 \qquad\textbf{(E)} ~2^{160}:1 \qquad</math> |
==Solution== | ==Solution== | ||
To be Released on April 26th. | To be Released on April 26th. | ||
Revision as of 17:42, 22 April 2021
Given that 
. Given that the product of the even divisors is 
, and the product of the odd divisors is 
. Find 
.
Solution
To be Released on April 26th.
