2021 JMC 10 Problems/Problem 1

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Problem

What is the value of \[\dfrac{20}{2\cdot1}  - \dfrac{2+0}{2/1}?\] $\textbf{(A) } 3 \qquad\textbf{(B) } 7 \qquad\textbf{(C) } 8 \qquad\textbf{(D) } 9 \qquad\textbf{(E) } 13$

Solution

We have $\frac{20}{2\cdot 1} - \frac{2+0}{2/1} = 10-1 = 9.$