Difference between revisions of "2021 JMPSC Accuracy Problems/Problem 1"

(Solution)
(Solution)
Line 5: Line 5:
 
== Solution ==
 
== Solution ==
  
We use the fact that 27 = 2^3<math> to conclude that the only multiples of </math>3<math> that are factors of </math>27<math> are </math>3<math>, </math>9<math>, and </math>27<math>. Thus, our answer is </math>3+9+27=\boxed{39)$
+
We use the fact that <math>27 = 2^3</math> to conclude that the only multiples of <math>3</math> that are factors of <math>27</math> are <math>3</math>, <math>9</math>, and <math>27</math>. Thus, our answer is <math>3 + 9 + 27 = 39</math>.
  
 
~Bradygho
 
~Bradygho

Revision as of 21:58, 10 July 2021

Problem

Find the sum of all positive multiples of $3$ that are factors of $27.$

Solution

We use the fact that $27 = 2^3$ to conclude that the only multiples of $3$ that are factors of $27$ are $3$, $9$, and $27$. Thus, our answer is $3 + 9 + 27 = 39$.

~Bradygho