Difference between revisions of "2021 JMPSC Accuracy Problems/Problem 2"

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The three biggest distinct positive integers that are <math>100</math> or less are <math>100</math>, <math>98</math>, and <math>96</math>. Thus, our answer is <math>\frac{100+98+96}{3} = \boxed{98}</math>.
 
The three biggest distinct positive integers that are <math>100</math> or less are <math>100</math>, <math>98</math>, and <math>96</math>. Thus, our answer is <math>\frac{100+98+96}{3} = \boxed{98}</math>.
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~Bradygho

Revision as of 22:04, 10 July 2021

Problem

Three distinct even positive integers are chosen between $1$ and $100,$ inclusive. What is the largest possible average of these three integers?

Solution

The three biggest distinct positive integers that are $100$ or less are $100$, $98$, and $96$. Thus, our answer is $\frac{100+98+96}{3} = \boxed{98}$.

~Bradygho