Difference between revisions of "2021 JMPSC Sprint Problems/Problem 2"
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| − | + | It is generally best to use the smallest number of coins with the most value, specifically the quarters, for taking away a big chunk of the problem. We are able to fit <math>11</math> quarters, or <math>\$2.75</math> into <math>\$2.78</math>. That only leaves <math>3</math> cents. We cannot put any nickels nor dimes, therefore we require three pennies to get a total of <math>\$2.78</math>. | |
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| + | The least number of coins Brady can use to pay off <math>\$2.78</math> will be <math>14</math> coins. | ||
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| + | -OofPirate | ||
Revision as of 00:44, 11 July 2021
Problem
Brady has an unlimited supply of quarters ($0.25), dimes ($0.10), nickels ($0.05), and pennies ($0.01). What is the least number (quantity, not type) of coins Brady can use to pay off $
?
Solution
It is generally best to use the smallest number of coins with the most value, specifically the quarters, for taking away a big chunk of the problem. We are able to fit 
quarters, or 
into 
. That only leaves 
cents. We cannot put any nickels nor dimes, therefore we require three pennies to get a total of .
The least number of coins Brady can use to pay off will be 
coins.
-OofPirate
