Difference between revisions of "2021 JMPSC Sprint Problems/Problem 6"
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| − | + | The probability in which a random choosing of a coin from a pool of <math>100</math> coins bringing out a nickel is <math>\frac{2}{5}</math>. Multiplying the fraction by <math>\frac{20}{20}</math>, we get <math>\frac{40}{100}</math>, or <math>40</math> coins out of <math>100</math>. This means that there are <math>40</math> nickels, and <math>60 dimes. | |
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| + | The value of </math>40<math> nickels is: </math>40\cdot 0.05=2.00<math>, or two dollars. | ||
| + | On the other hand, the value of </math>60<math> dimes is: </math>60 \cdot 0.10=6.00<math>, or </math>6<math> dollars. | ||
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| + | Therefore, Luis has a total of </math>6+2<math> </math>=<math> </math>\boxed{8}$ dollars total in dimes and nickels. | ||
Revision as of 01:00, 11 July 2021
Problem
Luis has 
coins that are all either nickels or dimes. If the probability of randomly picking a nickel from these coins is 
how much money does Luis have in dollars?
Solution
The probability in which a random choosing of a coin from a pool of coins bringing out a nickel is 
. Multiplying the fraction by 
, we get 
, or 
coins out of . This means that there are nickels, and $60 dimes.
The value of$ (Error compiling LaTeX. Unknown error_msg)40
40\cdot 0.05=2.00
60
60 \cdot 0.10=6.00
6$dollars.
Therefore, Luis has a total of$ (Error compiling LaTeX. Unknown error_msg)6+2$$ (Error compiling LaTeX. Unknown error_msg)=$$ (Error compiling LaTeX. Unknown error_msg)\boxed{8}$ dollars total in dimes and nickels.
