Difference between revisions of "2021 MECC Mock AMC 12"

(Blanked the page)
(Tag: Blanking)
Line 1: Line 1:
  
 +
 +
==Problem 25==
 +
25. All the solution of <math>(z-2-\sqrt{2})^{24}=4096</math> are vertices of a polygon. The smallest solution that when express in polar form, has a <math>y</math> value greater than <math>0</math> but smaller than <math>\frac{\pi}{2}</math> can be expressed as <math>\frac{\sqrt{a}+\sqrt{b}+i\sqrt{c}-i\sqrt{d}+\sqrt{e}+f+i\sqrt{g}-hi}{j}</math> which <math>a,b,c,d,e,f,g,h,j</math> are all not necessarily distinct positive integers, <math>i</math> in this case represents the imagenary number, <math>i</math>, and the fraction is in the most simplified form. Find <math>a+b+c+d+e+f+g+h+j</math>.

Revision as of 11:39, 21 April 2021


Problem 25

25. All the solution of $(z-2-\sqrt{2})^{24}=4096$ are vertices of a polygon. The smallest solution that when express in polar form, has a $y$ value greater than $0$ but smaller than $\frac{\pi}{2}$ can be expressed as $\frac{\sqrt{a}+\sqrt{b}+i\sqrt{c}-i\sqrt{d}+\sqrt{e}+f+i\sqrt{g}-hi}{j}$ which $a,b,c,d,e,f,g,h,j$ are all not necessarily distinct positive integers, $i$ in this case represents the imagenary number, $i$, and the fraction is in the most simplified form. Find $a+b+c+d+e+f+g+h+j$.