Difference between revisions of "2022 AMC 8 Problems/Problem 6"
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==Solution== | ==Solution== | ||
| + | |||
| + | Let the smallest number be <math>x.</math> It follows that the largest number is <math>4x.</math> | ||
| + | |||
| + | Since <math>x,15,</math> and <math>4x</math> are equally spaced on a number line, we have | ||
| + | <cmath>\begin{align*} | ||
| + | 4x-15 &= 15-x \\ | ||
| + | 5x &= 30 \\ | ||
| + | x &= \boxed{\textbf{(C) } 6}. | ||
| + | \end{align*}</cmath> | ||
| + | ~MRENTHUSIASM | ||
| + | ==Video Solution== | ||
| + | https://youtu.be/Ij9pAy6tQSg?t=409 | ||
| + | |||
| + | ~Interstigation | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2022|num-b=5|num-a=7}} | {{AMC8 box|year=2022|num-b=5|num-a=7}} | ||
{{MAA Notice}} | {{MAA Notice}} | ||
Revision as of 00:36, 19 February 2022
Contents
Problem
Three positive integers are equally spaced on a number line. The middle number is 
and the largest number is 
times the smallest number. What is the smallest of these three numbers?
Solution
Let the smallest number be 
It follows that the largest number is 
Since 
and 
are equally spaced on a number line, we have
~MRENTHUSIASM
Video Solution
https://youtu.be/Ij9pAy6tQSg?t=409
~Interstigation
See Also
| 2022 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
