2023 AMC 12A Problems/Problem 8
- The following problem is from both the 2023 AMC 10A #10 and 2023 AMC 12A #8, so both problems redirect to this page.
Contents
- 1 Problem
- 2 Solution 1
- 3 Solution 2 (Variation on Solution 1)
- 4 Solution 3 (do this if you are bored)
- 5 Solution 4 (Testing Answer Choices)
- 6 Solution 5
- 7 Video Solution by Math-X (First understand the problem!!!)
- 8 Video Solution by Power Solve (easy to digest!)
- 9 Video Solution (🚀 Just 3 min 🚀)
- 10 Video Solution by CosineMethod [🔥Fast and Easy🔥]
- 11 Video Solution
- 12 See Also
Problem
Maureen is keeping track of the mean of her quiz scores this semester. If Maureen scores an on the next quiz, her mean will increase by . If she scores an on each of the next three quizzes, her mean will increase by . What is the mean of her quiz scores currently?
Solution 1
Let represent the amount of tests taken previously and the mean of the scores taken previously.
We can write the following equations:
Multiplying equation by and solving, we get:
Multiplying equation by and solving, we get:
Solving the system of equations for and , we find that and .
~walmartbrian ~Shontai ~andyluo ~megaboy6679
Solution 2 (Variation on Solution 1)
Suppose Maureen took tests with an average of .
If she takes another test, her new average is
Cross-multiplying: , so .
If she takes more tests, her new average is
Cross-multiplying: , so .
But can also be written as . Therefore
~Dilip ~megaboy6679 (latex)
Solution 3 (do this if you are bored)
Let represent the sum of Maureen's test scores previously and be the number of scores taken previously.
So, and
We can use the first equation to write in terms of .
We then substitute this into the second equation:
From here, we solve for t: multiply both sides by () and then (), combining like terms to get . Factorize to get or , and therefore (makes sense for the problem).
We substitute this to get .
Therefore, the solution to the problem is
~milquetoast ~the_eaglercraft_grinder
Solution 4 (Testing Answer Choices)
Let's consider all the answer choices. If the average is , then, we can assume that all her test choices were . We can see that she must have gotten twice, in order for another score of to bring her average up by one. However, adding three 's will not bring her score up to 10. Continuing this process for the answer choices, we see that the answer is ~andliu766 (minor wording edit by mihikamishra)
Solution 5
Let be the number of existing quizzes. So after one more test, score has extra points to distribute to quizzes. Also, after three more quizzes, there will be extra points to distribute to the quizzes. So . This means . extra points means original mean (average) is
~Pratima
Video Solution by Math-X (First understand the problem!!!)
https://youtu.be/GP-DYudh5qU?si=fQ77Xhb7x1EP_Ieh&t=2361 ~Math-X
Video Solution by Power Solve (easy to digest!)
https://www.youtube.com/watch?v=ZUgo3-BKt30
Video Solution (🚀 Just 3 min 🚀)
~Education, the Study of Everything
Video Solution by CosineMethod [🔥Fast and Easy🔥]
https://www.youtube.com/watch?v=1QJ_BQOfZtg
Video Solution
~Steven Chen (Professor Chen Education Palace, www.professorchenedu.com)
See Also
2023 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 9 |
Followed by Problem 11 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |
2023 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 7 |
Followed by Problem 9 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.