Difference between revisions of "AoPS Wiki:Problem of the Day/June 4, 2011"

Revision as of 21:53, 3 June 2011

${x}$ is defined by the smallest positive decimal such that when subtracted from $x$ , you get an integer, and $0<\{x\}<1$

Find $x$ such that $10*\{x\}^2+\frac{\lfloor x \rfloor}{\lceil x\rceil}=\frac{9}{10}$

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-{x} is defined by the smallest positive decimal such that when subtracted from x, you get an integer, and <math>0<\{x\}<1</math>
+<math>{x}</math> is defined by the smallest positive decimal such that when subtracted from <math>x</math>, you get an integer, and <math>0<\{x\}<1</math>
-Find x such that <math>10*\{x\}^2+\frac{\lfloor x \rfloor}{\lceil x\rceil}=\frac{9}{10}</math>
+Find <math>x</math> such that <math>10*\{x\}^2+\frac{\lfloor x \rfloor}{\lceil x\rceil}=\frac{9}{10}</math><noinclude>[[category:Problem of the Day]]</noinclude>
-<noinclude>[[category:Problem of the Day]]</noinclude>