Difference between revisions of "AoPS Wiki:Problem of the Day/June 4, 2011"

Latest revision as of 23:26, 3 June 2011

Find $x$ where $0<x<1$ such that $10x^2+\frac{\lfloor x \rfloor}{\lceil x\rceil}=\frac{9}{10}$

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-{x} is defined by the smallest positive fraction such that when subtracted from x, you get an integer. <math>0<{x}<1</math>
+Find <math>x</math> where <math>0<x<1</math> such that <math>10x^2+\frac{\lfloor x \rfloor}{\lceil x\rceil}=\frac{9}{10}</math><noinclude>[[category:Problem of the Day]]</noinclude>
-Find x such that <math>10*{x}^2+\frac{\lfloor x \rfloor}{\lceil x\rceil}=\frac{9}{10}</math>
-<noinclude>[[category:Problem of the Day]]</noinclude>