# AoPS Wiki talk:Problem of the Day/August 1, 2011

## Problem

AoPSWiki:Problem of the Day/August 1, 2011

## Solution

*This Problem of the Day needs a solution. If you have a solution for it, please help us out by adding it.*
We can split this summation, as shown:
.

Now we must simply find each of the smaller sums, and add them.

:

We can use the formula for the sum of an infinite geometric series ( where is the first term and is the common ratio). and since each term is getting multiplied by to receive the next term. Therefore, this sum is: .

:

Similarly, we can use the formula used to solve the first part. and . Therefore, this sum is: .

Using these two answers, the desired sum is: .