Difference between revisions of "AoPS Wiki talk:Problem of the Day/July 4, 2011"

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{{:AoPSWiki:Problem of the Day/July 4, 2011}}
 
==Solution==
 
==Solution==
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<math>3^x-3 \equiv 0 \mod 16 \Rightarrow 3^x \equiv 3 \mod 16</math>
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So <math>3^x</math> cycles through 3,9,11,1 mod 16, <math>x = 1</math> doesn't work so try <math>x = 5</math> which works and we're done
 
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Revision as of 01:36, 4 July 2011

Problem

AoPSWiki:Problem of the Day/July 4, 2011

Solution

$3^x-3 \equiv 0 \mod 16 \Rightarrow 3^x \equiv 3 \mod 16$ So $3^x$ cycles through 3,9,11,1 mod 16, $x = 1$ doesn't work so try $x = 5$ which works and we're done This Problem of the Day needs a solution. If you have a solution for it, please help us out by adding it.

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