AoPS Wiki talk:Problem of the Day/July 8, 2011

Revision as of 01:26, 8 July 2011 by Ahaanomegas (talk | contribs) (Solution)

Problem

AoPSWiki:Problem of the Day/July 8, 2011

Solution

This Problem of the Day needs a solution. If you have a solution for it, please help us out by adding it.

By the Binomial Theorem, we have

$\begin {align*} \left(a-\frac{1}{\sqrt{a}}\right)^{7} &= a^7 + \dbinom {7}{1} (a^6) \left( - \frac {1}{\sqrt {a}} \right) + \dbinom {7}{2} (a^5) \left( - \frac {1}{\sqrt {a}} \right)^2 + \dbinom {7}{3} (a^4) \left( - frac {1}{\sqrt {a}} \right)^3 + \dbinom {7}{4} (a^3) \left( - \frac {1}{\sqrt {a}} \right)^4 + \dbinom {7}{5} (a^2) \left( - \frac {1}{\sqrt {a}} \right)^5 + 7 (a) \left( - \frac {1}{\sqrt {a}} \right)^6 + \left( - \frac {1}{\sqrt {a}} \right)^7 \\&= a^7 - 7a^{11/2} + 21 a^4 - 35 a^{5/2} + 35 a - 21 a^{-1/2} + 7a^{-3} - a^{-7/2}$ (Error compiling LaTeX. Unknown error_msg) So, the answer is $\boxed {-21}$.