Difference between revisions of "AoPS Wiki talk:Problem of the Day/June 12, 2011"

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{{:AoPSWiki:Problem of the Day/June 12, 2011}}
 
{{:AoPSWiki:Problem of the Day/June 12, 2011}}
 
==Solution==
 
==Solution==
{{potd_solution}}
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Let's take a look at the units digit of <math>39</math>, which is <math>9</math>. Now, let's take a look at the positive numbers that add up to to <math>9</math>:
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<cmath>1,8</cmath>
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<cmath>2,7</cmath>
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<cmath>3,6</cmath>
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<cmath>4,5</cmath>
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Now, we realize that every pair has an even element. Any number with an even units digit is even. So, what is the only even prime? <math>2</math>! So, one of our primes is <math>2</math>. The other is then, consequently, <math>37</math>. The product is then:
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<cmath>2\cdot{37}=\boxed{74}</cmath>

Latest revision as of 17:40, 11 June 2011

Problem

AoPSWiki:Problem of the Day/June 12, 2011

Solution

Let's take a look at the units digit of $39$, which is $9$. Now, let's take a look at the positive numbers that add up to to $9$:

\[1,8\]

\[2,7\]

\[3,6\]

\[4,5\]

Now, we realize that every pair has an even element. Any number with an even units digit is even. So, what is the only even prime? $2$! So, one of our primes is $2$. The other is then, consequently, $37$. The product is then:

\[2\cdot{37}=\boxed{74}\]