# Difference between revisions of "AoPS Wiki talk:Problem of the Day/June 7, 2011"

## Solution

$\sqrt{x+2}=x-18 \implies$ $x+2=(x-18)^2=x^2-36x+324 \implies$ $x^2-37x+322=0 \implies$ $(x-23)(x-14)=0$.

Clearly $x=14$ is extraneous, so our answer is $x=\boxed{23}$.