Difference between revisions of "Brute forcing"

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Given the problem "How many outfits can you create with thirteen hats and seven shoes?", a method involving brute force would be to list all 91 possibilities.
 
Given the problem "How many outfits can you create with thirteen hats and seven shoes?", a method involving brute force would be to list all 91 possibilities.
  
Another method of bruteforce is the Greedy Algorithm. As an example, given two sets <math>\{a_1,a_2,\ldots,a_n\}</math> and <math>\{b_1,b_2,\ldots,b_3\}</math> how can we maximize the sum of $\sum{i,j \in n} a_ib_j$ ? We sort the sets such that they are in increasing or decreasing order; then, the maximal sum is $a_1b_1 + a_2b_2 + a_3b_3 + \ldots a_nb_n$.  The "greedy" part is when we maximize the sum each step by taking the largest possible term to add.
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Another method of bruteforce is the Greedy Algorithm. As an example, given two sets <math>\{a_1,a_2,\ldots,a_n\}</math> and <math>\{b_1,b_2,\ldots,b_3\}</math> how can we maximize the sum of <math>\sum{i,j \in n} a_ib_j</math> ? We sort the sets such that they are in increasing or decreasing order; then, the maximal sum is <math>a_1b_1 + a_2b_2 + a_3b_3 + \ldots a_nb_n</math>.  The "greedy" part is when we maximize the sum each step by taking the largest possible term to add.
  
 
See the [[Rearrangment Inequality]] for consequences of the example(and a more formal proof).
 
See the [[Rearrangment Inequality]] for consequences of the example(and a more formal proof).

Revision as of 16:25, 18 June 2006

Brute forcing is generally accepted as the term for solving a problem in a roundabout, time-consuming, and inconvenient method.


Given the problem "How many outfits can you create with thirteen hats and seven shoes?", a method involving brute force would be to list all 91 possibilities.

Another method of bruteforce is the Greedy Algorithm. As an example, given two sets $\{a_1,a_2,\ldots,a_n\}$ and $\{b_1,b_2,\ldots,b_3\}$ how can we maximize the sum of $\sum{i,j \in n} a_ib_j$ ? We sort the sets such that they are in increasing or decreasing order; then, the maximal sum is $a_1b_1 + a_2b_2 + a_3b_3 + \ldots a_nb_n$. The "greedy" part is when we maximize the sum each step by taking the largest possible term to add.

See the Rearrangment Inequality for consequences of the example(and a more formal proof).