# Difference between revisions of "Ceva's theorem/Problems"

Etmetalakret (talk | contribs) (Created page with "==Introductory== ===I1=== ====Problem==== Suppose <math>AB, AC</math>, and <math>BC</math> have lengths <math>13, 14</math>, and <math>15</math>, respectively. If <math>\frac...") |
Etmetalakret (talk | contribs) |
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If <math>BD = x</math> and <math>DC = y</math>, then <math>10x = 40y</math>, and <math>{x + y = 15}</math>. From this, we find <math>x = 12</math> and <math>y = 3</math>. | If <math>BD = x</math> and <math>DC = y</math>, then <math>10x = 40y</math>, and <math>{x + y = 15}</math>. From this, we find <math>x = 12</math> and <math>y = 3</math>. | ||

− | ''[[Ceva' | + | ''[[Ceva's_theorem | Back to main article]]'' |

## Latest revision as of 15:16, 9 May 2021

## Contents

## Introductory

### I1

#### Problem

Suppose , and have lengths , and , respectively. If and , find and .

#### Solution

If and , then , and . From this, we find and .