Difference between revisions of "Derangement"

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==Notation==
 
==Notation==
The number of derangements of an <math>n</math>-element set is called the <math>n</math>th derangement number or the ''subfactorial'' of <math>n</math> and is sometimes denoted <math>!n</math>.  (Note that using this notation may require some care, as <math>a!b</math> can potentially mean both <math>(a!)b</math> and <math>a(!b)</math>.)  This number is given by the formula
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The number of derangements of an <math>n</math>-element set is called the <math>n</math>th derangement number or the ''subfactorial'' of <math>n</math> and is sometimes denoted <math>!n</math> or <math>D_n</math>.  (Note that using this notation may require some care, as <math>a!b</math> can potentially mean both <math>(a!)b</math> and <math>a(!b)</math>.)  This number satisfies the recurrences
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\[
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!n = n \cdot !(n - 1) + (-1)^n
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\]
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and
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\[
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!n = (n - 1)(!(n - 1) + !(n - 2))
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\]
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and is given by the formula
  
 
<cmath>!n = n! \sum_{k=0}^{n} \frac{(-1)^k}{k!}.</cmath>
 
<cmath>!n = n! \sum_{k=0}^{n} \frac{(-1)^k}{k!}.</cmath>

Revision as of 23:43, 10 January 2008

A derangement is a permutation with no fixed points. That is, a derangement of a set leaves no element in its original place. For example, the derangements of $\{1,2,3\}$ are $\{2, 3, 1\}$ and $\{3, 1, 2\}$, but $\{3,2, 1\}$ is not a derangement of $\{1,2,3\}$ because 2 is a fixed point.

Notation

The number of derangements of an $n$-element set is called the $n$th derangement number or the subfactorial of $n$ and is sometimes denoted $!n$ or $D_n$. (Note that using this notation may require some care, as $a!b$ can potentially mean both $(a!)b$ and $a(!b)$.) This number satisfies the recurrences

\[ !n = n \cdot !(n - 1) + (-1)^n \]

and

\[ !n = (n - 1)(!(n - 1) + !(n - 2)) \]

and is given by the formula

\[!n = n! \sum_{k=0}^{n} \frac{(-1)^k}{k!}.\]

Thus, the number derangements of a 3-element set is $3! \cdot \sum_{k = 0}^3 \frac{(-1)^k}{k!} = 6\cdot\left(\frac{1}{1} - \frac{1}{1} + \frac{1}{2} - \frac{1}{6}\right) = 2$, which we know to be correct.

Problems

Introductory

See also

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